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3 years ago

How to divide 10,200 by 350

Mathematics

1 answer:

netineya [11]3 years ago

4 0

29.9999 would be the answer here's how i worked it out

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What Number is X in this equation? 9 - 3 ÷ 1/3 + 1 = X

mario62 [17]

Answer:

Step-by-step explanation:

Use PEMDAS to solve the equation, and you will get the answer 1 for x

5 0

2 years ago

Read 2 more answers

Which expression will determine the perimeter, in inches, of the rectangle? O 10 x 7 10 + 7 O (2 x 7) + (2 x 10) O 10 x 7 x 7 x

fredd [130]

Answer:

$(2 * 7) + (2 * 10)$

Step-by-step explanation:

The missing details in the question are:

$Length = 10$

$Width = 7$

Required

The perimeter

This is calculated as:

$Perimeter = 2 * (Length + Width)$

So, we have:

$Perimeter = 2 * (10 + 7)$

Open bracket

$Perimeter = 2 * 10 + 2 * 7$

Rewrite as:

$Perimeter = (2 * 7) + (2 * 10)$

3 0

1 year ago

Read 2 more answers

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that y is a function of x :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ x ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

2 years ago

Find the slope of each line

MissTica

1. -10/9
2. 2/5
3. -2/5
4. 3/5
5. 1/10
6. -10/3

3 0

2 years ago

Which of the following points are solutions to the equation y= -2/3x+2

Llana [10]

$y=-\dfrac{2}{3}x+2\\\\\left(-\dfrac{2}{5};\ \dfrac{34}{15}\right)\to x=-\dfrac{2}{5};\ y=\dfrac{34}{15}\\\\for\ x=-\dfrac{2}{5}\to y=-\dfrac{2}{3}\cdot\left(-\dfrac{2}{5}\right)+2=\dfrac{4}{15}+2=\dfrac{4}{15}+\dfrac{30}{15}=\dfrac{34}{15}\\CORRECT\\\\\left(\dfrac{7}{2};\ \dfrac{13}{3}\right)\to x=\dfrac{7}{2};\ y=\dfrac{13}{3}\\\\for\ x=\dfrac{7}{2}\to y=-\dfrac{2}{3}\cdot\dfrac{7}{2}+2=-\dfrac{7}{3}+2=-\dfrac{7}{3}+\dfrac{6}{3}=-\dfrac{1}{3}\neq\dfrac{13}{3}\\INCORRECT$

$\left(\dfrac{1}{8};\ \dfrac{23}{12}\right)\to x=\dfrac{1}{8};\ y=\dfrac{23}{12}\\\\for\ x=\dfrac{1}{8}\to y=-\dfrac{2}{3}\cdot\dfrac{1}{8}+2=-\dfrac{1}{12}+2=-\dfrac{1}{12}+\dfrac{24}{12}=\dfrac{23}{12}\\CORRECT\\\\\left(\dfrac{8}{3};\ \dfrac{2}{3}\right)\to x=\dfrac{8}{3};\ y=\dfrac{2}{3}\\\\for\ x=\dfrac{8}{3}\to y=-\dfrac{2}{3}\cdot\dfrac{8}{3}+2=-\dfrac{16}{9}+2=-\dfrac{16}{9}+\dfrac{18}{9}=\dfrac{2}{9}\neq\dfrac{2}{3}\\INCORRECT$

Answer: (-2/5,34/15) and (1/8,23/12).

3 0

2 years ago