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stira [4]
3 years ago
9

Can someone please help me with question? Thanks if you do!

Mathematics
1 answer:
maw [93]3 years ago
3 0
If I did my math correct I got a
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Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
a washer and a dryer cost $640 combined. the washer cost $60 less than the dryer . what is the cost of the dryer?
Delvig [45]

Answer:

380

Step-by-step explanation:

640/2=320

320-60=260

640-260=380

5 0
3 years ago
Read 2 more answers
These are the first six terms of a sequence with a = 2:
inn [45]

Answer:

a_{n} = 9a_{n-1}

Step-by-step explanation:

Note there is a common ratio r between consecutive terms of the sequence, that is

r = 18 ÷ 2 = 162 ÷ 18 = 1458 ÷ 162 = 13122 ÷ 1458 = 9

A recursive formula allows a term in the sequence to be found by multiplying the previous term by the common ratio, that is

a_{n} = 9a_{n-1} with a₁ = 2

7 0
3 years ago
I need to know what the value is for x
hoa [83]
4/6 = x + 3/ 12 - x
4( 12 - x) = 6( x + 3)
48 - 4x = 6x + 18
-4x - 6x = 18 - 48
- 10x = -30
x = 3
6 0
3 years ago
Dwight made double the number of baskets in the second half of the basketball game than in the first half. He made 5 baskets in
Anarel [89]

He made 10 baskets because yoh must double 5

5 0
3 years ago
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