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Cloud [144]
3 years ago
6

The 6th term of an arithmetic progression is 35 and the 13th term is 77. find the 20th term​

Mathematics
1 answer:
Helga [31]3 years ago
5 0

20th term= 119

Step-by-step explanation:

Let the first term of AP be a

and common difference be d

nth term is given by,

= a+(n-1)d

6th term = 35

a+(6-1)d= 35

a+5d=35 -----------------(i)

13th term = 77

a+12d= 77----------------(ii)

Now, equation (ii) - (i)

a+12d-(a+5d)= 77-35

a+12d-a-5d= 42

7d=42

d=6

Now, from equation (i)

a= 35-5d= 35-5(6)= 35-30 = 5

20th term= a+19d= 5+19(6)= 119

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Given the line segment , state the ratio of the segment partitions as. Be sure to reduce fractions
Effectus [21]

Answer/Step-by-step explanation:

Line segment AB consists of segment AC and segment CB.

AC = 7 cm

CB = 21 cm

The entire segment, AB = 21 + 7 = 28cm

The ratio of the segments partitions can be stated as follows:

Ratio of AC to CB = AC:CB = 7:21 = 1:3 = \frac{1}{3}

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3 years ago
An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th
Irina-Kira [14]
Given that the volume of the aquarium is 20m^3.

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Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is \sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by 8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h

Area of the four side faces of the aquarium is 4 times the length of the base times the height = 4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}

Total area to be covered by grass is the base and the four side faces and is given by \frac{20}{h}+\sqrt{320h}

Cost of the entire metal frame = 7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h

Cost of the entire grass = 8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h

Therefore, total cost in terms of the height, h, is given by

C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h
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