What is the greatest common factor of 28x²y-7xy^5?

2 answers:

8 0

7xy would be the greatest common factor. You can divide both terms by 7xy. 7 goes into 28 4 times ad you can factor out both an x and a y from both terms. You would end up with: 7xy(4x-y^4).

Alchen [17]2 years ago

3 0

The greatest common factor of this can be solved by looking at the individual parts and splitting it up.

First, we have 28 and 7. Well, thats an easy one. 7 goes into 28 4 times so we are now left with 4 and 1.

We can also write the rest of this like this 4(x*x*y) - 1(x*y*y*y*y*y)

Now, what values are in both equations. We have one x and one y that can be taken out of both.

We end up with 7xy(4x-7y^4)

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$\bf \textit{perimeter of a rectangle}=p=side+side+side+side
\\\\
or\implies p=w+w+l+l\implies p=2w+2l
\\\\
p=2(w+l)\qquad 
\begin{cases}
w=width\\
l=length\\
------\\
p=48
\end{cases}\implies 40=2(w+l)\\\\
-----------------------------\\\\
\textit{area of it}=A=w\cdot l\qquad \begin{cases}
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l=length\\
------\\
A=40
\end{cases}\implies 40=wl\\\\
-----------------------------\\\\$

$\bf thus\qquad 
\begin{cases}
40=2(w+l)\to \frac{40}{2}=w+l\to\frac{40}{2}-l=\boxed{w}
\\\\
40=wl\\
--------------\\
40=\left( \boxed{\frac{40}{2}-l} \right)\cdot l
\end{cases}$

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