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chubhunter [2.5K]
3 years ago
6

8. (7.MS-PS3-5.) When energy changes form, energy is

Physics
1 answer:
Furkat [3]3 years ago
5 0

Answer:

Not lost or created

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A constant force of 10 N is applied to an object. The object accelerates at a constant rate of 4 m/s2. What is the mass of the o
tatuchka [14]

Answer:

I think it is 2.5 kg.

Explanation:

I can say you do:

Fnet = m * a

So, you want to find mass:

m = Fnet / a

So, the answer you will receive is 2.5

7 0
3 years ago
HELP THIS IS LATE How does the size and temperature of the Sun compare to other stars in the Milky Way galaxy?
Verizon [17]

Answer:ya.\

Explanation:

5 0
3 years ago
The distance covered by a car at a time, t is given by x = 20t + 6t4, calculate
Anni [7]

Answer:

(i) v = 44 m/s

(ii) a = 72 m/s^2

Explanation:

You have the following equation for the potion of a car:

x=20t+6t^4

(i) The instantaneous velocity is the derivative of x in time:

\frac{dx}{dt}=20+(6)(4)t^3=20+24t^3

for t = 1 is:

v(t=1)=\frac{dx}{dt}=20+24(1)^3=44m/s

(ii) The instantaneous acceleration is the derivative of the velocity:

\frac{dv}{dt}=24(3)t^2=72t^2

for t = 1

a(t=1)=\frac{dv}{dt}=72(1)^2=72m/s^2

8 0
4 years ago
Initially at rest a single-stage rocket is launched vertically from the ground. The rocket’s thrust overcomes gravity and provid
Lelechka [254]

Answer:

Explanation:

Let a be the acceleration of launch. In 10 seconds , Distance gone up in 10 seconds

s = 1/2at²

= .5 x a x 100

=50a

Velocity after 10 s

u = at = 10a

Now 50a distance in downward direction is travelled in 20 s with initial velocity 10a in upward direction.

s = ut + 1/2 gt²

50a = -10ax20 + .5 x 10x400

250a = 2000

a = 8 m s⁻² .

Velocity after 10 s

= at = 80 m/s

further height reached with this speed under free fall

h = v² / 2g

= 80 x 80 / 2 x 10

= 320 m

height achieved under acceleration

= 50a

= 50 x 8 = 400m

Total height

= 320 + 400= 720 m

velocity after falling from 720 m

v² = 2gh = 2 x10 x 720

v = 120 m/s

7 0
3 years ago
Read 2 more answers
A car is traveling at some speed when it accelerates at 6 m/s2 for 3 seconds. If the car travels 39 meters in this time, how fas
Alchen [17]

Answer:

4 m/s

Explanation:

Given:

Δx = 39 m

a = 6 m/s²

t = 3 s

Find: v₀

Δx = v₀ t + ½ at²

39 m = v₀ (3 s) + ½ (6 m/s²) (3 s)²

v₀ = 4 m/s

6 0
3 years ago
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