Answer:
The awnser is d
Explanation:
i know cause i took the test
The answer is radiation I believe
You have to find interia using I=mr^2.
m=75+10
radius = 11
Then you have to substitute in first formula above to find the angular speed.
14020=(75+10)x v x 11
v= 14020/ (85x11) = 15m/s
To find linear speed, use V=wr.
Equation: V = 11*1.363 = 15m/s = 33.6mi/hr
Hope this helps! :)
Answer: 8.43 m
Explanation:
Given
Mass of the rocket, m = 600 g = 0.6 kg
Speed of riling, v = 2.5 m/s
F = mg, where
F = weight of the rocket in N
m = mass of the rocket in kg
g = acceleration due to gravity in m/s²
F = 0.6 * 9.8
F = 5.88 N
Since the the vertical thrust on the rocket is 8 N and 5.88 N of it will be used to counter the rockets weight. Thus, the remaining 2.12 N is what is available to provide acceleration.
Upward acceleration of the rocket is..... F = ma, a = F / m
a = 2.12 / 0.6
a = 3.53 m/s²
using equation of motion, we will calculate how long it will take to rise 20 m in the air
S = ut + 1/2at², where u = 0
20 = 1/2 * 3.53 * t²
t² = 4. / 3.53
t² = 11.33
t = √11.33 = 3.37 s
The distance then is
v = Δx / t, such that
Δx = v * t
Δx = 2.5 * 3.37
Δx = 8.43 m
