F = (mass)(acceleration) = ma
m = 0.25 kg
Vi = 16 m/s
t = 2 s
Vf = 0 m/s (since it was put to stop)
a=(Vf-Vi)/t
a=(0-16)/2
a = 8 m/s^2 (decelerating)
F = ma = (0.25 kg)(8 m/s^2)
F = 2 N
<span>Hope
this answer will be a good h<span>elp for you.</span></span>
yes because your mass doesn't change but your weight can
ex- if you travel to Saturn your weight would change but your mass would stay the same
Explanation:
It is given that,
Force applied to object, 
Position, 
(b) The cross product of force and position vector is used to find the net torque about the z axis. It is given by :
or
The torque is acting in -z axis.
(a) The magnitude of torque is given by :
Hence, this is the required solution.
Answer:
270 m/s²
Explanation:
Given:
α = 150 rad/s²
ω = 12.0 rad/s
r = 1.30 m
Find:
a
The acceleration will have two components: a radial component and a tangential component.
The tangential component is:
at = αr
at = (150 rad/s²)(1.30 m)
at = 195 m/s²
The radial component is:
ar = v² / r
ar = ω² r
ar = (12.0 rad/s)² (1.30 m)
ar = 187.2 m/s²
So the magnitude of the total acceleration is:
a² = at² + ar²
a² = (195 m/s²)² + (187.2 m/s²)²
a = 270 m/s²
Use v = u + at
Message me if you need more help
