All categories

3 years ago

Factor 2x^3+3x^2-23x-12, given that x+4 is a factor

2 answers:

6 0

Hello,
$2x^3+3x^2-23x-12\\
=2x^3+8x^2-5x^2-20x-3x-12\\
=2x^2(x+4)-5x(x+4)-3(x+4)\\
=(x+4)(2x^2-5x-3)\\
=(x+4)(2x^2-6x+x-3)\\
=(x+4)[2x(x-3)+1(x+3)]\\
=(x+4)(x-3)(2x+1)$

Alex73 [517]3 years ago

5 0

You might be interested in

Simplify the expression completely. (5√50-3√200+3√18)

Kaylis [27]

Answer:

$4\sqrt{2}$

Step-by-step explanation:

$5\sqrt{50} - 3\sqrt{200} + 3\sqrt{18}$ =

= $25\sqrt{2} - 30\sqrt{2} + 9\sqrt{2}$ = $4\sqrt{2}$

8 0

3 years ago

Read 2 more answers

Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe

AlekseyPX

The answer is
$\frac{-6i-3}{5}$ .

Before we rationalize the denominator, we must simplify the numerator and denominator. We evaluate the square root on the top, and combine like terms on the bottom:
$\frac{\sqrt{-9}}{(4-7i)-(6-6i)}
\\
\\=\frac{\sqrt{9i^2}}{4-6-7i--6i}
\\
\\=\frac{3i}{-2-i}$

To rationalize the denominator, we multiply by the conjugate. The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign. The conjugate of -2-i is -2+i:

$\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}
\\
\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}
\\
\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}
\\
\\=\frac{-6i+3i^2}{4-2i+2i-i^2}
\\
\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}$

7 0

3 years ago

An astronaut who weighed 150 pounds on Earth found that his weight on Jupiter was 400 pounds. He captured an alien that weighed

Andrews [41]

The alien would be about 20 LBS on the earth

3 0

3 years ago

Class A has 15 pupils and class B has 29 pupils.

Vaselesa [24]

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Class A has 15 pupils and class B has 29 pupils. The mean score for class A is 55. Hence:

Mean score of A = (sum of all scores) / 15

55 = (sum of all scores) / 15

sum of all scores in A = 825

The mean score for both classes is 76. Hence:

[(sum of all scores in A) + (sum of all scores in B)]/(total number of pupils) = mean score of both classes

[825 + (sum of all scores in B)]/(15 + 29) = 76

sum of all scores in B = 2519

Mean score of B = (2519) / 29 = 86.86

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

Find out more on equation at: brainly.com/question/13763238

#SPJ1

6 0

1 year ago

If CP of an item is Rs 7000, If SP of item is Rs 9100 Find the profit percentage.

Mama L [17]

Step-by-step explanation:

please mark me as brainlest

5 0

2 years ago