Write an equation in slope intercept form that goes through the point (5,-7) and is PARALLEL to the line y=-3x+8

Radda [10]

A- could be a part and/or a percent

b- 32×25%=8, 32-8=24

5 0

3 years ago

Grady drove 34 miles to his grandmas house. Next he drove 48 miles to visit his uncle. The trip took 90 minutes. If he drove at

Alona [7]

Answer:

55 mph

Step-by-step explanation:

speed = 54.6667 miles per hour

approximately 55 miles per hour

hope this helps! :D

have a miraculous day!! <3

*plus, your stick student's dinner is pizza!! :D*

5 0

2 years ago

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$

$\sigma = 3.5795$

<em>See attachment for result of 1-VarStats</em>

8 0

2 years ago

What set of numbers are shaded on the hundred chart.

Elden [556K]

Can we get a picture?

6 0

2 years ago

PLEASE HELP !!!!!!!!!! Alexia spent 3 minutes working on each of her math problems and 4 minutes on each of her science problem

Lunna [17]

The correct answer to this problem is the third statement which is "Alexia completed 20 math problems and 10 science problem". The following conditions are stated in the problem:
Alexia can answer 3 minutes on each math problem
Alexia can answer 4 minutes on each science problem
She worked more than 60 minutes
We have the inequality 3x + 4y > 60 where x represents the total number of math problem while y represents the total number of the science problem.
in our answer, we have x=20and y=10
3*20 + 4*10 > 60
60 + 40 > 60
100 > 60

Therefore, our answer is correct.

7 0

2 years ago

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