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2 years ago

Write an equation in slope intercept form that goes through the point (5,-7) and is PARALLEL to the line y=-3x+8

Mathematics

1 answer:

Arlecino [84]2 years ago

4 0

Answer:

there is no line parallel to y = -3x + 8 that goes through (5, -7). this point falls on this line

Step-by-step explanation:

$y = - 3x + 8$

$- 7 = - 3(5) + b \\ - 7 = - 15 + b \\ b = 8$

The answer is

$y = - 3x + 8$

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Evaluate: \frac{23}{56} + \frac{3}{8} - ( - \frac{4}{28} )

MrMuchimi

I think this is what you mean. I don't know why the Latex didn't work. Good for you that you can use it.

$\frac{23}{56} + \frac{3}{8} - \frac{-4}{28}$
$\frac{23}{56} + \frac{3}{8} - \frac{-4}{28}$ Reduce the 4/28 to 1/7
$\frac{23}{56} + \frac{3}{8} - \frac{-1}{7}$ Make the 2 minuses into a +
$\frac{23}{56} + \frac{3}{8} + \frac{1}{7}$ 56 is the common denominator.
$\frac{23}{56} + \frac{21}{56} + \frac{8}{56}$

Answer = [23 + 21 + 8] / 56 = 52 / 56 = 13 / 14 When both numerator and denominator are divided by 4

13 / 14 <<<< answer.

5 0

2 years ago

-8/9 divided by -8/9 in fraction form

AVprozaik [17]

Answer:

Step-by-step explanation:

If you ever divide a number by itself, it will be 1.

8 0

2 years ago

Read 2 more answers

2. Express the given statement as an algebraic expression. Sum ofa and 5 divided by 8

bezimeni [28]

Answer:

An algebraic expression for Sum of a and 5 divided by 8 is $\mathbf{\frac{a+5}{8}}$

Step-by-step explanation:

We need to express the given statement as an algebraic expression.

Sum of a and 5 divided by 8

Basically, we are given the expression in English sentence and we have to write algebraic expression.

It can be done in two steps:

Sum of a and 5 = We know that sum is denoted by + sign. So, we get (a+5)

Sum of a and 5 divided by 8 = $\frac{a+5}{8}$

So, An algebraic expression for Sum of a and 5 divided by 8 is $\mathbf{\frac{a+5}{8}}$

7 0

3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$