Area of a circle: π x r x r
area of the rectangle = 13x6=78
area of unshaded semi circle (circle) =
π x 3 x 3 = 28.274 ≈ 28.27
78-28.27=49.73 (in 2 decimal place)
if it’s not in 2 decimal place then it’s 49.726
<span>the equation is -16t^2+150t+50, the middle term being the upward velocity and the last term being the height it started at.
The vertex is at -150/-32=4.6875, and the height is 401.56 feet
Setting the equation equal to zero,
-16t^2+150t+50=0 or 16t^2-150t-50=0
t=(1/32) { 150 +/- sqrt (22500+3200)}, where sqrt (25700)=160.31
t=(1/32)310.31=9.697 sec or 9.7 seconds TIME TO LANDING
</span><span>0---50
1--184
2--286
3--356
</span><span>4--394
5--400
6--374
7--316
8--226
9--104
10--has hit
</span><span>axis of symmetry is at vertex or t=4.6875
</span><span>negative values would imply the rocket was rising up through the building.</span>
Where are the following equations?
Answer:
![525\pi](https://tex.z-dn.net/?f=525%5Cpi)
Step-by-step explanation:
Volume of a cylinder is given by the function ![v=\pi r^{2}h](https://tex.z-dn.net/?f=v%3D%5Cpi%20r%5E%7B2%7Dh)
where v is volume, r is radius and h is height.
In order to find the radius we just divide the diameter in half and get
![\frac{10}{2} =5=r](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B2%7D%20%3D5%3Dr)
now we just plug the values in the formula
![v=\pi r^{2}h\\=\pi (5^{2})(21)\\=\pi (25)(21)\\=525\pi](https://tex.z-dn.net/?f=v%3D%5Cpi%20r%5E%7B2%7Dh%5C%5C%3D%5Cpi%20%285%5E%7B2%7D%29%2821%29%5C%5C%3D%5Cpi%20%2825%29%2821%29%5C%5C%3D525%5Cpi)
Answer:
It is B because
Step-by-step explanation:
3 x 9 x 4 = 108