Answer:
Graph y = 2x
Step-by-step explanation:
First, let's get the equation into standard form. Distribute the 2 on the right.
Next, we want the variable "y" to be alone, so we at 4 to both sides.
That is our equation in standard y = mx + b form. "m" is our slope, while "b" is our y-intercept. Above , we don't have a value for b, therefore the line passes through the origin.
We do, however, have a slope, which can be thought of as 
or rise over run. To represent this, we can rewrite our slope as:
Meaning in each interval, the line goes up by 2 units, and moves forward by 1.
62 triangle a and 59 triangle b
Short Answer: The first three are absolutely true. Congruency is maintained if all you are doing is shifting the figure 8 spaces away. Since the figures are congruent, their corresponding parts are equal and the statements made are always true. That's the guiding principle.
A is true. See the short answer.
B is True. You have gone 8 units away. The distance between the old G and the new one is 8 units. This is not a congruency property but it is true because it is given. You haven't altered the shape or rotatated it.
C is true by conguency. You have just shifted things 8 units. You have maintained equality and you have maintained distance between corresponding parts.
That leaves D. If the figures are regular, that will be true. If they are not regular, non corresponding external angles cannot be guaranteed to be true.
Answer:
b
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u><em>The options of the question are</em></u>
2(x − 1)2 = 4
2(x − 1)2 = −4
2(x − 2)2 = 4
2(x − 2)2 = −4
we have
This is a vertical parabola open upward
The vertex represent the minimum value
The quadratic equation in vertex form is
where
a is a coefficient
(h,k) is the vertex
so
Convert the quadratic equation in vertex form
Factor 2 leading coefficient
Complete the squares
Rewrite as perfect squares
The vertex is the point (1,-4)
Move the constant to the right side
