<span>Methyl groups
</span>DNA<span> methylation is a process by which </span>methyl groups<span> are added to the </span>DNA<span> molecule. Methylation can change the activity of a </span>DNA<span> segment without changing the sequence.</span>
Answer:
See the answer below
Explanation:
A DNase is also known as deoxyribonuclease and it is an enzyme that catalyzes the degradation of deoxyribonucleic acid by cleaving the phosphodiester linkage in their structures. Thus,<em> if the RNA is treated with a DNase before the plants are exposed to it, it will not make any difference. The plants will develop the same types of lesions as if they have been exposed to the mosaic virus.</em>
Unlike DNase, RNase is a ribonuclease, an enzyme that is capable of carrying out catalytic degradation of ribonucleic acids. <em>This means that if the RNA is treated with RNase before the plants are made to be exposed to it, they will not develop the lesions because the RNA would have been degraded by the enzyme.</em>
A protease is an enzyme that degrades the structure of proteins. <em>Treating a RNA with protease will thus have no effect on the structure of the RNA. Exposing the plants to the protease-treated RNA will make no difference. The plants will still come down with the lesions as if they have been exposed to the virus. </em>
Corrected Question:
The picture shows the dihybrid cross of 2 guinea pigs.
1. What is the genotype of the parents?
2. What is the phenotype of the parents?
3. What is the genotype of their baby guinea pig (in the empty box)?
a. BbRr - black rough fur
b. Bbrr - black smooth fur
c. bbRr- white rough fur
d. bbrr - white smooth fur
Answer:
Genotype of parents is BbRr as seen in the cross.
Phenotype of the parents is black rough furred.
The genotype of the baby in the empty box is bbRR.
Option D
<h3><u>
Explanation:</u></h3>
This representation of the genetic crossing is called as Punnet square, after the name of the scientist who discovered this process to denote the probability of finding the required genotype in a statistical way.
Here both the parents are heterozygous black and rough furred, with the genotype of BbRr.
So the gametes from the parents are = BR, Br, bR, and br from both the parents which are represented in the Punnet square.
Thus we can get 16 types of genetic combinations among the offsprings.
