10=s÷2+7 it really difficult could yall help me out

Mathematics

1 answer:

vladimir2022 [97]3 years ago

8 0

Answer:

The value of s is "90". A further explanation is given below.

Step-by-step explanation:

The given expression is:

⇒ 10=s÷2+7

i.e,

⇒ $10=\frac{s}{2+7}$

On solving the above expression, we get

⇒ $10=\frac{s}{9}$

On applying cross-multiplication, we get

⇒ $10\times 9=s$

⇒ $90 = s$

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ANTONII [103]

Megan:
x to the one third power = $x ^{1/3}$
<span>x to the one twelfth power = </span> $x ^{1/12}$

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span> $\frac{x ^{1/3}}{x ^{1/12}}$
<span>
Since </span> $\frac{ x^{a} }{ x^{b} } = x ^{a-b}$
then $\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}$

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

$\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}$

Julie:
x times x to the second times x to the fifth = x * x² * x⁵

<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span> $\sqrt[32]{x* x^{2} * x^{5} }$
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Since </span> $x^{a}* x^{b}= x^{a+b}$
Then $\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }$

Since $\sqrt[n]{x^{m}} = x^{m/n} }$
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Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.

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