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horrorfan [7]
3 years ago
6

Help me How...............

Mathematics
1 answer:
Hatshy [7]3 years ago
5 0
Here are the blank entries
#1 is b
#2 is h (maybe?)
#3 is a
#4 is i (maybe?)
#5 is g
#6 is e
#7 is d
#8 is j (hmm...)
hope these  answers help!
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PLZZZZ HAAALLLPPPP!!!!!
Harrizon [31]

Answer:

0

Step-by-step explanation:

-9x -3(2) = 6

-9x + 6 = 6

-9x + 6 -6 = 6-6

-9x/ -9= 0/-9

x=0

6 0
3 years ago
Which graph shows the solution set for |x - 3| < 4?
ikadub [295]

Answer:

see below

Step-by-step explanation:

|x - 3| < 4

To remove the absolute values, we need to make two inequalities, one positive and one negative

x-3 < 4     and     x-3 > -4

Add 3 to each side

x-3+3<4+3     and  x-3+3 > -4+3

x<7        and        x >-1

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4 0
3 years ago
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I am not sure how sigma notation works, can somebody explain how to solve this? It isn't the second choice.
Masja [62]

Answer:

first answer is correct

Step-by-step explanation:

Hello, we want to write 2 + 4 + 6 + ... + 20

for n = 1, 2n = 2*1 =2

for n = 2, 2n = 2*2=4

for n = 3, 2n=2*3=6

etc

so

\displaystyle \sum_{n=1}^{10} {2n} = 2*1 + 2*2 +2*3+2*4+...+2*10=2+4+6+8+...+20

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6 0
2 years ago
A function f defined by f(x) = x² + px + q is such that f(3) = 6 and f¹(3) = 0. Find the value of q.
CaHeK987 [17]

Answer:

q = 15

Step-by-step explanation:

Given

f(x) = x² + px + q , then

f(3) = 3² + 3p + q = 6 , that is

9 + 3p + q = 6 ( subtract 9 from both sides )

3p + q = - 3 → (1)

---------------------------------------

f'(x) = 2x + p , then

f'(3) = 2(3) + p = 0, that is

6 + p = 0 ( subtract 6 from both sides )

p = - 6

Substitute p = - 6 into (1)

3(- 6) + q = - 3

- 18 + q = - 3 ( add 18 to both sides )

q = 15

5 0
3 years ago
When 5 randomly selected people all have the same birth month of March.
Doss [256]

Answer:

I know 4 people that are all really close friends and all have birthdays in march.

Step-by-step explanation:

3 0
3 years ago
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