The total surface area of the remaining solid is 48(4+✓3) centimeters square.
<h3>How to calculate the surface area?</h3>
Through a regular hexagonal prism whose base edge is 8 cm and the height is 12 cm, a hole in the shape of a right prism.
The formula for the total surface area will be:
= Total surface area=2(area of the base)+ parameter of base × height
where,
Height= 8cm
Parameter of base=12(2) = 24
Area of the base= 6×✓3/4×4² = 64✓3/4
The surface area of the remaining solid will be:
= 2(64✓3/4) + 24 × 8
= 2(64✓3/4 + 192
With the hole is a rhombus prism with the following parameters:
diagonal 1 = 6, diagonal 2 = 8, height = 12
The volume is:
V1 =0.5 × d1 × d2 × h
V1 = 0.5 × 6 × 8 × 12
V1 = 96
The dimensions of the hexagonal prism are:
Base edge (a) = 8
Height (h) = 12
The volume is
V2 = (3✓(3)/2)a²h
V2 = (3✓3)/2) × 8² × 12
V2 = 1152✓3
The remaining volume is
V = V2 -V1
V = 1152✓3 - 96
Learn more about the hexagonal prism on:
brainly.com/question/27127032
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N=64.
32+64=100
64/8=8
sqrt (64+225)= sqrt (289) = positive and negative 17
F(x) = 1 - x
f(-3) = 1 - (-3)
f(-3) = 4
Answer:
Step-by-step explanation:
The rectangular prism has a volume equal to V=xyz. V=(1/3)3(5/3)=5/3 in^3. The cube has a volume equal to V=s^3. The volume of the cube is equal to the prism when
![s^3=(1/3)(3)(5/3)\\ \\ s^3=5/3\\ \\ s=\sqrt[3]{\frac{5}{3}}in\\ \\ s\approx 1.19in](https://tex.z-dn.net/?f=s%5E3%3D%281%2F3%29%283%29%285%2F3%29%5C%5C%20%5C%5C%20s%5E3%3D5%2F3%5C%5C%20%5C%5C%20s%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B5%7D%7B3%7D%7Din%5C%5C%20%5C%5C%20s%5Capprox%201.19in)
