Are you trying to set up the equation?
the equation: 24(2)+6=n
Answer:
We readily separate the variables and integrate:
∫dP/P=∫(k+bcos2
t)dt
ln P=kt+(b/2)*sin2t+ln C
Clearly C = Po, so we find that P(t) = Poexp(kt + (b/2)* sin 2t). The 271- curve with the typical numerical values P_o = 100, k = 0.03, and b = 0.06. It oscillates about the curve which represents natural growth with P_o and k = 0.03. We see that the two agree at the end of each full year.
note:
find the attached graph
In this question, we're trying to find cost of one sandwich.
To find this, we must make a systems of equation from the given information:
We would represent sandwiches as "s" and drinks as "d".
Systems of equations:
6s + 4d = 53
4s + 6d = 47
Solve for s:
6(6s + 4d = 53)
-4(4s + 6d = 47)
36s + 24d = 318
-16s - 24d = -188
--------------------------
20s = 130
Divide both sides by s
s = 6.50
This means that one sandwich costs $6.50
Answer:
$6.50
