Slant height of tetrahedron is=6.53cm
Volume of the tetrahedron is=60.35
Given:
Length of each edge a=8cm
To find:
Slant height and volume of the tetrahedron
<u>Step by Step Explanation:
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Solution;
Formula for calculating slant height is given as
Slant height=
Where a= length of each edge
Slant height=
=
=
=6.53cm
Similarly formula used for calculating volume is given as
Volume of the tetrahedron=
Substitute the value of a in above equation we get
Volume=
=
=
Volume=
=60.35
Result:
Thus the slant height and volume of tetrahedron are 6.53cm and 60.35
5 x 3 = 15
Ty spent $15 on binders
We know that m<JKL = m<JKM + m<MKL
Let's substitute the values from the picture into our equation above.
10x - 11 = 43 + 8x - 20
Combine like terms.
10x - 11 = 8x + 23
Subtract 8x from both sides and add 11 to both sides.
2x = 34
Divide both sides by 2
x = 17
m<MKL = 8x - 20 = 8(17) - 20 = 136 - 20 = 116 degrees.
m<JKL = 10x - 11 = 10(17) - 11 = 170 - 11 = 159 degrees.
Answer: 4/3
Step-by-step explanation:
You would find this answer because if x is 0 then it is just 2 then when you multiply 3 x 4/3 you get 4 then when you add that by two you get 6
Hopes this helps
Answer:
The hypotenuse is square root of 65
Step-by-step explanation:
a^2 + b^2 = c^2
legs of the right triangle are a and b. Just substitute 4 for a and 7 for b and solve.
4^2+7^2=16+49=65
c^2=65
Find the square root of both sides to get
c=the square root of 65
