I can answer the slopes
Answer:
1. would have a slope of 2
2. would have a slope of -1.66
3.would have a slope of 0
4. would have a slope of -13
Step-by-step explanation:
(Y2 - Y1) / (X2 -X1)
1. (9-5) / (4-2) = 4 / 2 =2
2. (-5-5) / (3 - -3) = -10 / 6 = 1.66
3. (2 - 2) / (5 - -4) = 0 / 9 = 0
4. (-7 - 6) / (3 - 3) = -13 / 0 = -13
Answer:
a. volume= 784 is the answer
Factor by grouping. Group up the terms into pairs, factor each pair, then factor out the overall GCF.
x^3 + 2x^2 - 16x - 32
(x^3 + 2x^2) + (-16x-32) ... pair up terms
x^2(x + 2) + (-16x - 32) ... factor x^2 from the first group
x^2(x + 2) - 16(x + 2) ... factor -16 from the second group
(x^2 - 16)(x + 2) .... factor out (x+2)
(x - 4)(x + 4)(x + 2) .... Use the difference of squares to factor x^2-16
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The original expression completely factors to (x - 4)(x + 4)(x + 2)
The three factors are x - 4 and x + 4 and x + 2
The initial value of 100 that doubles over each interval.
without the answer choices, I can only describe it and give you an example of the graph.
I'm assuming the function is 100*(2)^x because if it is as listed it would be a quadratic function with a vertical stretch of 100.
Answer:
a) N(P) = -6P + 16000
b) slope = -6 computers per dollar
That means the number of computer sold reduce by 6 per dollar increase in price.
c) ∆N = -660 computers
Step-by-step explanation:
Since N(P) is a linear function
N(P) = mP + C
Where m is the slope and C is the intercept.
Case 1
N(1000) = 10000
10000 = 1000m + C ....1
Case 2
N(1700) = 5800
5800 = 1700m + C ....2
Subtracting equation 1 from 2
700m = 5800 - 10000
m = -4200/700
m = -6
Substituting m = -6 into eqn 1
10000 = (-6)1000 + C
C = 10000+ 6000 = 16000
N(P) = -6P + 16000
b) slope = -6 computers per dollar
That means the number of computer sold reduce by 6 per dollar increase in price.
Slope is the change in number of computer sold per unit Change in price.
c) since slope m = -6 computers per dollar
∆P = 110 dollars
∆N = m × ∆P
Substituting the values,
∆N = -6 computers/dollar × 110 dollars
∆N = -660 computers.
The number of computer sold reduce by 660 when the price increase by 110 dollars
