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andrezito [222]
3 years ago
9

How do you classify a triangle by its sides and then by its angles ?

Mathematics
1 answer:
beks73 [17]3 years ago
6 0
Well classifying by sides would either be equilateral, scalene or isosceles....and by angles it would be acute, right or obtuse
 
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Factor the trinomial below. x2 – 2x – 35 A. (x – 5)(x + 7) B. (x – 5)(x – 7) C. (x + 5)(x – 7) D. (x + 5)(x + 7)
Sophie [7]
c. (x + 5)(x - 7)    use the FOIL method.

x² + 5x - 7x - 35

x² + (5x - 7x) - 35   collect like terms.

x² - 2x - 35   

hope that helps, God bless!
3 0
3 years ago
Read 2 more answers
Five cubes are lined up to form a solid. The side lengths of the cubes are 1 ft, 2 ft, 3 ft, 4 ft, and 5 ft. What is the volume
sdas [7]
First, you find the volume of each individual cube, and then you add everything up.  

 1^3 +2^3+3^3+4^3 + 5^3 = 225 

hope this helped :)
3 0
4 years ago
How many solutions does the equation have?
borishaifa [10]
First we have to distribute the parentheses on the left side, 2*x is 2x and 2*-3 is -6, so now the equation is 4x+2x-6 = 8x+12
Then, we can add together the two x's on the left side,
so now we have 6x-6 = 8x+12       Subtract 12 from both sides and
you get 6x -18 = 8x    Then you can subtract 6x from both the sides and get
-18 = 2x  Now we can divide both sides by 2, and the final answer is -9 = x
Since they are not the same and the two sides aren't unequal, there is one solution(:
Hope this is helping you(:
4 0
3 years ago
A merchant can place 8 large boxes or 10 small boxes into a carton for shipping. In one shipment, he sent a total of 96 boxes. I
alukav5142 [94]
To figure this out, you should think about the multiples of 10 boxes you could have.

If I had 10 small boxes, there would need to be 86 large boxes. 86 is not evenly divisible by 8 so that doesn't work.

If I had 20 small boxes, there would be 76 large boxes. 76 is not evenly divisible by 8.

If I had 30 small boxes, there would be 66 large boxes. 66 is not evenly divisible by 8.

If I had 40 small boxes, there would be 56 large boxes. 56 is every divisible by 8.

4 cartons of 10 small boxes and 7 cartons of 8 large boxes would be needed. This is a total of 11 cartons.
6 0
3 years ago
How to solve <br> 1.x^2+x-3<br> 2.x^2-2x+1<br> 3.3x+4<br> 4.-4x-8<br> 5.2x^2+3x+8
IgorC [24]

Answer:

How to solve 1.x^2+x-3 2.x^2-2x+1 3.3x+4 4.-4x-8 5.2x^2+3x+8. sksksskdkdkakeakeake; Mathematics. Marcus scored 3/5 as many points as David soccer in a basketball game David scored 20 points

Step-by-step explanation:

How to solve 1.x^2+x-3 2.x^2-2x+1 3.3x+4 4.-4x-8 5.2x^2+3x+8. sksksskdkdkakeakeake; Mathematics. Marcus scored 3/5 as many points as David soccer in a basketball game David scored 20 points

8 0
3 years ago
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