Given:
The square base pyramid with height 3 cm and base edge 2 cm.
To find:
The volume of the square pyramid.
Solution:
Volume of a square base pyramid is:
...(i)
Where, B is the base area and h is the height of the pyramid.
Base is a square with edge 2 cm, so the base area is:
Where, a is the edge of the square base.
Putting 
in (i), we get
Therefore, the volume of the given pyramid is 4 cm³.
Answer:
Step-by-step explanation:
The given system of equations is now reduced:
1) 
, 
, 
, 
Given
2) 
By 1)
3) 
2) in 1)
4) 
By 1)
5) ![[c+(b+c)]+b = c](https://tex.z-dn.net/?f=%5Bc%2B%28b%2Bc%29%5D%2Bb%20%3D%20c)
4) in 3)
6) 
Algebra
7) 
Algebra
8) 
7) in 4)/Algebra
9) 
7) and 8) in 2)/Algebra
10) 9), 1), 7) and 8)/Algebra/Result
Answer:
y = -3/2x + 2
Step-by-step explanation:
Since you know it has a point at (0, 2) - the y intercept, put those values into the equation and solve. To be perpendicular it seems the reciprocal of the slope with the opposite sign, so 2/3 is the original slope, and -3/2 becomes the new slope.
y = 2/3x + 8 becomes
2 = -3/2(0) + b We substitute in the x and y values, but we have to figure out what the last number will be.
2 = 0 + b
b = 2
So put the whole equation together
y = -3/2x + 2
