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3 years ago

Details pls not short answer

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

6 0

Answer:

Step-by-step explanation:

a) Bilal is y years and his mother is 25 years older that he is

Bilal's mother is = 25 + y years old

b) adding Bilal and his mother's age

= y + 25 + y

= 2y + 25

c) when Bilal is 12 I.e. y = 12

His mum will be

= 12 + 25

= 37

Ksenya-84 [330]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

Given that Bilal is age y and his mother is 25 years older, then

a. Bilal's mothers age is y + 25

b. the sum of their ages = y + y + 25 = 2y + 25

c. Mother is y + 25 = 12 + 25 = 37 years

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Question Help Suppose that the lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a

koban [17]

Answer:

a)3.438% of the light bulbs will last more than 6262 hours.

b)11.31% of the light bulbs will last 5252 hours or less.

c) 23.655% of the light bulbs are going to last between 5858 and 6262 hours.

d) 0.12% of the light bulbs will last 4646 hours or less.

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

In this problem, we have that:

The lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a standard deviation of 333.3 hours.

So $\mu = 5656, \sigma = 333.3$

(a) What proportion of light bulbs will last more than 6262 hours?

The pvalue of the z-score of $X = 6262$ is the proportion of light bulbs that will last less than 6262. Subtracting 100% by this value, we find the proportion of light bulbs that will last more than 6262 hours.