Answer:
Last paragraph
Explanation:
Finally, Jeremey has also divided the problem into smaller parts, such as production costs, overheads, downtime expense, repair expenditure, and so on.
Answer:
correct option is $0
Explanation:
given data
purchased truck = $270,000
transportation and calibration costs = $30,000
life = 20 years
financed period = 15 year
solution
we know here that some expenses like insurance and depreciation etc is allocated by systematic and the rational procedure for some period
so that during that period related asset is expected to provide the benefit
and acquisition of capital asset is not record as expenses
we know appropriate property and plant or the equipment assets account are debit on purchases
so that Depreciation expenses are recorded to reflect the allocation of costs of the asset to operation over service life of assets
so here correct option is $0
Answer:
$700
Explanation:
If a bond is issued at a lower price than the face value of the bond, then the bond is issued on the discount. This discount is amortized over the bond's life. This amortization will be expensed as Interest Expense.
Discount = Face value - Issuance price = $15,000 - $14,700 = $300
Bond's Life = 6 years
Amortization of discount = $300 / 6 = $50 annually = $25 semiannually
Coupon Payment = Face Value x coupon Rate = $15,000 x 9% = $1.350 annually = $675 semiannually
Interest Expense Includes both the coupon payment and discount amortization for the period.
Interest Expense = $675 + $25 = $700
Answer:
1. Cost of the old X-ray machine - SC
2. The salary of the head of the Radiology Department - None
3. The salary of the head of the Pediatrics Department - None
4. Cost of the new laser printer - DC
5. Rent on the space occupied by Radiology - None
6. The cost of maintaining the old machine - DC
7. Benefits from a new DNA analyzer - OC
8. Cost of electricity to run the X-ray machines - DC
Where,
SC - Sunk cost
DC - Differential cost
OC - Opportunity cost