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Marat540 [252]
3 years ago
9

Determine the molecular and empirical formulas for the substance shown in the ball-and-stick model below.

Chemistry
1 answer:
notka56 [123]3 years ago
8 0
Molecular formula: C8H6N2

Empirical formula: C4H3N
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Calculate the heat released when 454 grams of steam at 100 degrees C condenses.
sasho [114]
<h3>Answer:</h3>

1026.05 kJ

<h3>Explanation:</h3>
  • The Quantity of heat is calculated by multiplying the mass of a substance by specific heat capacity and the change in temperature.
  • However, condensation takes place at a constant temperature.
  • Therefore, Quantity of heat is calculated by multiplying mass by the latent heat of vaporization.
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In this case we are given;

Mass of steam as 454 g

To calculate the amount of heat released we must know the value of latent heat of vaporization;

The latent heat of vaporization of steam is 2260 J/g

Therefore;

Heat released, Q = 454 g × 2260 J/g

                             =1026040 Joules

But, 1000 joules = 1 kilo-joules

Thus, Q = 1026.04 kJ

Hence, the amount of heat released is 1026.05 kJ

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Hope this helps:)

Have a great day:)

Please mark me brainiest

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