All categories

3 years ago

Question 5 (1 point)

Chemistry

1 answer:

Marianna [84]3 years ago

7 0

Answer:

P=12.16 atm

Explanation:

Using the formula of ideal gas law:

PV = nRT

P= nRT/V

n= number of moles

R= Avogadro constant = 0.0821

T= Temperature in K => ºC + 273.15 K

P= (1.50 moles)(0.0821)( 296.15 K)/ 3.00L

P= 12.15

You might be interested in

How many moles of glucose does 1.2 x 10^24 molecules represent

sammy [17]

<h3>Answer:</h3>

2.0 mol C₆H₁₂O₆

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.2 × 10²⁴ molecules C₆H₁₂O₆ (glucose)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 1.2 \cdot 10^{24} \ molecules \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{6.022 \cdot 10^{23} \ molecules \ C_6H_{12}O_6})$
Divide: $\displaystyle 1.99269 \ mol \ C_6H_{12}O_6$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.99269 mol C₆H₁₂O₆ ≈ 2.0 mol C₆H₁₂O₆

3 0

3 years ago

The _________ indicates that 70% of the Sun's radiation is contained on Earth and 30% is reflected back into space.

vichka [17]

i think it would be Earth's albedo hope this helps

4 0

3 years ago

Read 2 more answers

What is the edge length of a face-centered cubic unit cell that is made of of atoms, each with a radius of 154 pm

gladu [14]

Answer:

The edge length of a face-centered cubic unit cell is 435.6 pm.

Explanation:

In a face-centered cubic unit cell, each of the eight corners is occupied by one atom and each of the six faces is occupied by a single atom.

Hence, the number of atoms in an FCC unit cell is:

$8*\frac{1}{8} + 6*\frac{1}{2} = 4 atoms$

In a face-centered cubic unit cell, to find the edge length we need to use Pythagorean Theorem:

$a^{2} + a^{2} = (4R)^{2}$ (1)

Where:

a: is the edge length

R: is the radius of each atom = 154 pm

By solving equation (1) for "a" we have:

$a = 2R\sqrt{2} = 2*154 pm*\sqrt{2} = 435.6 pm$

Therefore, the edge length of a face-centered cubic unit cell is 435.6 pm.

I hope it helps you!

7 0

3 years ago

The acid dissociation constant ka for an unknown acid ha is 4.57 x 10^-3 what is the base dissociation constant kb for th econju

SashulF [63]

Answer:

2.19 x 10^-12.

Explanation:-

The relation between Ka and Kb for an acid and it's conjugate base is

Ka x Kb = Kw where Kw = ionic product of water.

So Kb = 10^-14 / (4.57 x 10 ^ -3)

= 2.19 x 10^-12

4 0

3 years ago

Iron reacts with cl2 according to the equation 2 fe(s) + 3 cl2(g) ? 2 fecl3(s). how many moles of cl2 is needed to react with 4.

IceJOKER [234]

2Fe + 3Cl₂ ---> 2FeCl₃

4.4mol of Fe, you have a 2:3 ratio of Fe to Cl₂ so divide 4.4/2 = 2.2 and multiply by three 2.2 x 3 = 6.6mol of Cl₂

hope that helps :)

8 0

3 years ago

Read 2 more answers