Answer:
![Cp_{liquid}=2.54\frac{J}{g\°C}](https://tex.z-dn.net/?f=Cp_%7Bliquid%7D%3D2.54%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D)
Explanation:
Hello,
In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:
![Q_{Ag}=-Q_{liquid}](https://tex.z-dn.net/?f=Q_%7BAg%7D%3D-Q_%7Bliquid%7D)
That in terms of the heat capacities, masses and temperature changes turns out:
![m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})](https://tex.z-dn.net/?f=m_%7BAg%7DCp_%7BAg%7D%28T_2-T_%7BAg%7D%29%3D-m_%7Bliquid%7DCp_%7Bliquid%7D%28T_2-T_%7Bliquid%7D%29)
Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:
![Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}](https://tex.z-dn.net/?f=Cp_%7Bliquid%7D%3D%5Cfrac%7Bm_%7BAg%7DCp_%7BAg%7D%28T_2-T_%7BAg%7D%29%7D%7B-m_%7Bliquid%7D%28T_2-T_%7Bliquid%7D%29%7D%20%5C%5C%5C%5CCp_%7Bliquid%7D%3D%5Cfrac%7B31.2g%2A0.237%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%2A%2828.3-227.2%29%5C%C2%B0C%7D%7B185.8g%2A%2828.3-24.4%29%5C%C2%B0C%7D%5C%5C%20%5C%5CCp_%7Bliquid%7D%3D2.54%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D)
Best regards.
Inherited it from his grandfather
Answer:
C
Explanation:
The answer is C because only that amount can move
Answer:
Giá trị xà phòng hóa hoặc số xà phòng hóa (SV hoặc SN) biểu thị số miligam kali hydroxit (KOH) hoặc natri hydroxit (NaOH)