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Vsevolod [243]
3 years ago
13

Simplify the expressions. Show your work. (x + 6)^2

Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0
The answer is x^2+12x+36
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mr lippman bought a dryer for 160 bucks and sold it for 240 bucks. if overhead expenses were 20% of the selling price, what was
lana [24]
<span>First calculate the amount of overhead expenses. The selling price was $240. To find 20% of 240, multiply 240 by 0.20, which equals 48. From that, we found that the overhead expenses were $48. To find the rate of profit, take the selling price and subtract all expenses. We know that Mr Lippman's selling price was $240, he spent $160 to buy the dryer, and he had $48 worth of overhead expenses. 240 - 160 - 48 = 32. Therefore, the profit was $32. To find the rate of profit, divide the profit by the total expenses. 32 / (240 + 160) = 0.08. Therefore, the rate of profit was 8%.</span>
5 0
4 years ago
Dalton is playing a game in which the object is to obtain a 0 by adding the points scored during each round
Katen [24]
The answer to this question is 52
3 0
3 years ago
A 40 meter ladder makes an angle of 32° with the playground. How far is the bottom of the ladder from the base of the playground
postnew [5]

Answer:

33.9 m

Step-by-step explanation:

cos(32) = adjacent/hypotenuse

cos(32) = X/40

X = 40cos(32)

X = 33.92192385 m

4 0
4 years ago
8(1 - 5x) = 13 in mixed numbers
tangare [24]
Perform indicated multiplications on left side.

8-40x=13  subtract 8 from both sides

-40x=5  divide both sides by -40

x=-5/40

x=-1/8

Note: There are no mixed numbers in this problem.
8 0
3 years ago
Read 2 more answers
All 6 members of a family work. Their hourly wages (in dollars) are the following.37, 38, 39, 40, 39, 11Assuming that these wage
tiny-mole [99]

We have a sample that in fact represents the population.

We have to calculate the standard deviation of this population.

The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).

We have to start by calculating the mean of the population first:

\begin{gathered} \mu=\dfrac{1}{n}\sum ^n_{i=1}\, x_i \\ \mu=\dfrac{1}{6}(37+38+39+40+39+11) \\ \mu=\dfrac{204}{6} \\ \mu=34 \end{gathered}

Now, we can calculate the standard deviation as:

\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}

Answer: the standard deviation of this population is approximately 10.33

3 0
2 years ago
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