To be divisible by both 7 and 8 a number must be a multiple of 56.
Multiples of 56 are just 56n. We wish to know the largest of three digit numbers that is a multiple of 56 then. So:
56n<1000
n<1000/56
n<17.86 and since n must be an integer n=17
Then the largest three digit multiple of 56 is:
56(17)=952
Answer:
Options A and B
i.e., A. 4(3) and B.
Step-by-step explanation:
Like radicals are similar to like terms.
For example,
x, 2x, -10x, , 7.3x are like terms.
are some more examples of like terms.
Similarly, like radicals are:
etc.
Hence, from the given options, like radicals to are:
A. and B.
Answer:
2 x 5 = 10
10 x a = 10a
answer = 10a
Step-by-step explanation:
the answer on top is step by step
Perimeter Formula:
Area Formula:
Set perimeter Formula equal to b:
Plug formula for be we just made above into the area Formula:
Solve for L (you'll have to use quadratic formula) then plug that back into the area Equation and solve for b.
Here's a link to where the problem has been explained before (they go into more detail than me).
https://brainly.ph/question/468631
lmk if you need any more help