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Licemer1 [7]
3 years ago
15

$680 at 8% for 48 months​

Mathematics
2 answers:
madreJ [45]3 years ago
7 0

Answer:

2611.2

Step-by-step explanation:

I dont think its right though

Tanzania [10]3 years ago
7 0

Answer:

30 028.8 US$

Step-by-step explanation:

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(a) For the accompanying data set, draw a scatter diagram of the data.
lidiya [134]

Answer:

a) n=5 \sum x = 30, \sum y = 25, \sum xy = 162, \sum x^2 =206, \sum y^2 =155  

r=\frac{5(162)-(30)(25)}{\sqrt{[5(206) -(30)^2][5(155) -(25)^2]}}=0.42967  

So then the correlation coefficient would be r =0.430 rounded

b) Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0  

Because the correlation coeffcient is positive and the absolute value of the correlation coefficient 0.430 is not greater than the critical value for this dataset, no linear relation exists between x and y.

And the reason is because we fail to reject the null hypothesis.

Step-by-step explanation:

Part a

We have the following data:

x: 2  6  6  7  9

y: 3  2  6  9  5

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=5 \sum x = 30, \sum y = 25, \sum xy = 162, \sum x^2 =206, \sum y^2 =155  

r=\frac{5(162)-(30)(25)}{\sqrt{[5(206) -(30)^2][5(155) -(25)^2]}}=0.42967  

So then the correlation coefficient would be r =0.430 rounded

Part b

In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:

Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0

The statistic to check the hypothesis is given by:

t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}

And is distributed with n-2 degreed of freedom. df=n-2=5-2=3

In our case the value for the statistic would be:

t=\frac{0.430\sqrt{5-2}}{\sqrt{1-(0.430)^2}}=0.825

The critical value for n =5 is given by the table attached. We can see that the critical value is r_{crit}= 0.878, and then the final conclusion would be:

Because the correlation coeffcient is positive and the absolute value of the correlation coefficient 0.430 is not greater than the critical value for this dataset, no linear relation exists between x and y

And the reason is because we fail to reject the null hypothesis.

4 0
2 years ago
Which list of numbers is shown on the number line? help please a b c or d I give you 20 or 30 points please answer me!
lisov135 [29]

Answer:

B

Step-by-step explanation:

6 2/9 is 6.2, and sqrt 42 is 6.48

4 0
2 years ago
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PLZ HELP!!! Will mark brainliest if answers are correct and give a thanks with rating of 5. I'm being timed I need answer as soo
attashe74 [19]

Answer:

79 cents per song

Step-by-step explanation:

you divide 1580 by 20 and get 79 and then re-add the decimal place in to get .79

6 0
3 years ago
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*How can I find the sum of -5 + 12 using a vertical number line? *
antoniya [11.8K]
QqqqqqwqqwffdhvdhbxeZ chiita hexhhrdbbb fc gvcgxehnbcgbvb hnohvb mloibddgzzc loco ducrxbjv
4 0
3 years ago
Solve: f(x)=2x^2+10x+12 using the Quadratic Formula, show work.<br> Will mark brainiest
Archy [21]
F(x)=2+10+-12 using the
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3 years ago
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