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patriot [66]
3 years ago
8

Can you help me please?

Mathematics
1 answer:
9966 [12]3 years ago
6 0
First, change the two mixed numbers in the expression into an improper fraction: 25/6 + 5/3.
Then, find the Lowest Common Denominator of both fractions, which is 6, and set both denominators equal to that.  Remember, whatever you do on one side you must do to the other: 25/6 + 10/6
Add the two together: 25/6 +10/6 = 35/6.
To make it a mixed number again, find how many times 6 goes into 35, which is 5 times, with a remainder of 5.  Your answer is 5 5/6
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Solve the following inequality 90 > 10x + 80
Lera25 [3.4K]

Answer:

x<1

Step-by-step explanation:

10x + 80 < 90

10x < 90 - 80

10x < 10

x < 1

3 0
3 years ago
Only tick questions please help me​
goldfiish [28.3K]
6/76 x 3
Jsjsjjsjsjsjjsja
8 0
3 years ago
Use Laplace transform methods to solve the differential equation: The initial conditions are f(0) = 0 and <img src="https://tex.
Llana [10]

Answer:

Step-by-step explanation:

\frac{d^2 y}{dt^2} +12\frac{dy}{dt} +32y = 10e^{-2t} where f(x) is replaced by y

Take Laplace on both sides

s^2 Y -s(0)-0 +12s Y-0+32Y = \frac{10}{s+2} \\Y(s^2+12s+32) =  \frac{10}{s+2}\\Y =  \frac{10}{(s+2)(s+4)(s+8)}

We can resolve into partial fraction to get Y = L(y)

Let this equals

\frac{A}{s+2} +\frac{B}{s+4} +\frac{C}{s+8} \\10 = A(s+4)(s+8) + B(s+2)(s+8) +Cs+4)(s+2) \\

Solving we get

s=-9

24C = 10 or C =5/12

s=-2:  A=10/12=5/6

s=-4: B = -5/4

Taking inverse Laplace

y(t) = \frac{-5e^{-4t} }{4} + \frac{5e^{-8t} }{12} +\frac{-5e^{-2t} }{6}

6 0
3 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
andre [41]

Answer:

○ \displaystyle sin\:θ = \frac{12}{13}

Explanation:

This should help you figure out why this is the answer:

\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ

I am joyous to assist you anytime.

8 0
3 years ago
In an 18-meter race between a tortoise and a hare, the tortoise leaves 23 minutes before the hare. The hare, by running at an av
seropon [69]
We know that:
time=distance/speed
if the tortoise speed is x m/min, then since 0.5 m/hr=1/120 m/min
18/x=23+18/(x+1/120)
solving for x we get:
x=0.08 m/min
speed of hare is:
(0.08+1/120)=0.088 m/min

6 0
3 years ago
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