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Novosadov [1.4K]
3 years ago
9

For questions 8 – 10, answer the questions about tangent-tangent angles.

Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

m(arc ZWY) = 305°

Step-by-step explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

                                                   = \frac{1}{2}(220-140)

                                                   = \frac{1}{2}(80)

                                                   = 40°

9). Following the same rule as above,

Angle formed between two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

125 = \frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]

250 = [m(\text{arc ZWY})-m(\text{arc ZY})]

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) = \frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])

                          = \frac{1}{2}(254-106)

                          = \frac{148}{2}

                          = 74°

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