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Reil [10]
3 years ago
12

I’ll DO ANYTHING IF U ANSWER THIS WHOLE THING

Mathematics
1 answer:
Oxana [17]3 years ago
4 0

Answer:

13/12

Step-by-step explanation:

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nevsk [136]

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Step-by-step explanation:

i can't see the full equation

3 0
3 years ago
What’s the answer for #5 everyone keeps putting different answers
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4 years ago
Meyer uses 6 loads of gravel to cover 2/5 of his driveway. How many loads of gravel will he need to cover his entire driveway
Mekhanik [1.2K]
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5 0
3 years ago
How many integers between 27 and 53 have a remainder of 4 divided by 6
marusya05 [52]

Answer:

There are 4 integers between 27 and 53 that have a remainder of 4 divided by 6.

Step-by-step explanation:

At first we need to find which integers between 27 and 53 are divisible by 6, which are, respectively:

A =\{30, 36, 42, 48\}

All integers that have a remainder of 4 divided by 6 are found by summing 4 to each element of A, that is:

A' = \{34,40,46, 52\}

There are 4 integers between 27 and 53 that have a remainder of 4 divided by 6.

8 0
4 years ago
What is the 1st term when -5z^2+7z^4+11z-8z^3 is arranges in descending order
Alexandra [31]

Answer: The first term is 7z^{4}


Step-by-step explanation:

1. To rewrite the given polynomial in descending order, you must see the exponent of each variable of the terms. Then, you must arrange the terms from bigger to smaller.

2. Keeping this on mind, you have:

7z^{4}-8z^{3}-5z^{2}+11z

3. As you can see, the first term is: 7z^{4}


6 0
4 years ago
Read 2 more answers
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