Let one odd integer = x
other odd integer = x +2
Sum = x + x+2 = -44
=> 2x + 2 = -44
=> 2x = -44 -2 = -46
=> x = -46/2 = -23
x+2 = -23 + 2 = -21
Integers are -23 and -21
<span>April had </span><span>3/7</span><span> of a pound of pecans. Her sister ate </span><span>2/3</span><span> of April's pecans. How many pounds of pecans did April's sister eat?
Answer:2/7
Explaining </span><span>3/7</span><span> x </span><span>2/3</span><span> = </span><span>621</span><span> = </span><span>2/7
Good Luck! :)
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Answer:
D) no solution
Step-by-step explanation:
1/ (x-2) + 1/(x+2) = 4/(x^2-4)
x cannot equal 2 or -2 since that would make our fractions equal 1/0 or be undefined
Factor the term on the right
1/ (x-2) + 1/(x+2) = 4/(x-2)(x+2)
Multiply both sides by (x-2) (x+2)
(x-2) (x+2) (1/ (x-2) + 1/(x+2)) = 4/(x-2)(x+2)*(x-2) (x+2)
Distribute
x+2 + (x-2) = 4
Combine like terms
2x = 4
Divide by 2
2x/2 = 4/2
x =2
But this is not a possible solution since that is not in the domain
Hello, please consider the following.
![\displaystyle \begin{aligned} \int\limits^x {5sin(5t)sin(t)} \, dt &= -\int\limits^x {5sin(5t)} \, d(cos(t))\\ \\&=-[5sin(5t)cos(t)]+ \int\limits^x {25cos(5t)cos(t)} \, dt\\\\&=-5sin(5x)cos(x)+ \int\limits^x {25cos(5t)} \, d(sin(t))\\ \\&=-5sin(5x)cos(x)+[25cos(5t)sin(t)]+ \int\limits^x {25sin(5t)sin(t)} \, dt\\\\&=-5sin(5x)cos(x)+25cos(5x)sin(x)+ \int\limits^x {(25*5)sin(5t)sin(t)} \, dt\end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7D%20%5Cint%5Climits%5Ex%20%7B5sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%20%26%3D%20-%5Cint%5Climits%5Ex%20%7B5sin%285t%29%7D%20%5C%2C%20d%28cos%28t%29%29%5C%5C%20%5C%5C%26%3D-%5B5sin%285t%29cos%28t%29%5D%2B%20%5Cint%5Climits%5Ex%20%7B25cos%285t%29cos%28t%29%7D%20%5C%2C%20dt%5C%5C%5C%5C%26%3D-5sin%285x%29cos%28x%29%2B%20%5Cint%5Climits%5Ex%20%7B25cos%285t%29%7D%20%5C%2C%20d%28sin%28t%29%29%5C%5C%20%5C%5C%26%3D-5sin%285x%29cos%28x%29%2B%5B25cos%285t%29sin%28t%29%5D%2B%20%5Cint%5Climits%5Ex%20%7B25sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%5C%5C%5C%5C%26%3D-5sin%285x%29cos%28x%29%2B25cos%285x%29sin%28x%29%2B%20%5Cint%5Climits%5Ex%20%7B%2825%2A5%29sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%5Cend%7Baligned%7D)
And we can recognise the same integral, so.

And then,

Thanks