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slava [35]
3 years ago
8

Rewarding BRAINLY FOR CORRECT ANSWER file = report

Mathematics
2 answers:
dezoksy [38]3 years ago
8 0
4,-4 is the answer to this problem
GrogVix [38]3 years ago
4 0

Answer:

(-4,-4)

Step-by-step explanation:

You might be interested in
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
Eric made a scale drawing of the auditorium. The stage, which 15 35 feet wide in real life,
Molodets [167]
Based on the given conditions, formulate: 5/35
Simplify by dividing by dividing the numerator and denominator by 5: 1/7

Therefore the scale of the drawing is 1/7
7 0
2 years ago
2x+1y=25 <br> find the equation of x
leonid [27]

Answer:

x=

−1

2

y+

25/2

Step-by-step explanation:

Let's solve for x.

2x+1y=25

Step 1: Add -y to both sides.

2x+y+−y=25+−y

2x=−y+25

Step 2: Divide both sides by 2.

2x

2

=

−y+25

2

x=

−1

2

y+

25

2

8 0
3 years ago
PLS HELP ME ITS DUE IN 4 MINS!<br><br> Subtract 2y²+7y+2 from 6y²+9y−8.
Dmitry_Shevchenko [17]

Answer:

-4y^2 - 2y + 10

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Help in your answer!​
mart [117]

Answer:

Two different transformations happen. Rotation/Reflection and translation (I say rotation/reflection because they can both put the parabola where it is after being transformed)

(Rotation- 180 degrees)

(Reflection across its it's starting point)

Translation- pushed up 4 points from negative 4 to 0 on the y-axis

When you put the parent function into a graph it is positive so the u is opening upward and starts at -4. Both sides of the u go through the points (0,0)and (4,0).

But in the transformed function is negative so the u opens downward. The sides going through the points (0,-4) and (4,-4)

I hope this makes sense

4 0
3 years ago
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