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frozen [14]
3 years ago
13

Write an algebraic expression for the following word phrase. The quotient of 62 and x

Mathematics
1 answer:
madreJ [45]3 years ago
5 0

Answer:

62/x

Step-by-step explanation:

You might be interested in
Seven hotdogs and four hamburgers cost $13. Four hotdogs and seven hamburgers cost $14.50. How much does one hamburger cost and
viva [34]

Answer:

hotogs=$1.50  hamburgers=$1

Step-by-step explanation:

h=hotdog b=hamburger

7h+4b=13

4h+7b=14.5

(7h+4b=13)-4b

4h+7b=14.5

 

h=-0.57b+1.86

4h+7b=14.5

8 0
3 years ago
HELP ME PLSSSSSS!!!!
katovenus [111]

Answer:

the answer you have chosen is right.

Step-by-step explanation:

A rational number can be written as a simplified fraction, and or is a recurring or finite decimal. That is the only number that can be properly written according to the rules I just stated.

7 0
3 years ago
Simplify (8x^3-5x-1)-(7x^2+6x-10)
irakobra [83]

Answer:

8x^3-7x^2-11x+9

Step-by-step explanation:

(8x^3-5x-1)-(7x^2+6x-10)

remove unnesasary ( )

8x^3-5x-1 -(7x^2+6x-10)

the distribute

8x^3-5x-1 -7x^2-6x+10

combine like terms

8x^3-11x+9-7x^2

use the communative property to reorder the equation

8x^3-7x^2-11x+9

4 0
3 years ago
Hi help with these please and thank yu? :)
ryzh [129]

Answer:

the first one is A

b/c when you calculate it comes 0 = 6

And the second one is D

b/c when you calculate it comes 0 = 2

if it's helpful ❤❤❤

THANK YOU.

7 0
3 years ago
Guys help please I am struggling
alina1380 [7]

9514 1404 393

Answer:

  14.1 years

Step-by-step explanation:

Use the compound interest formula and solve for t. Logarithms are involved.

  A = P(1 +r/n)^(nt)

amount when P is invested for t years at annual rate r compounded n times per year.

Using the given values, we have ...

  13060 = 8800(1 +0.028/365)^(365t)

  13060/8800 = (1 +0.028/365)^(365t) . . . . divide by P=8800

Now we take logarithms to make this a linear equation.

  log(13060/8800) = (365t)log(1 +0.028/365)

Dividing by the coefficient of t gives us ...

  t = log(13060/8800)/(365·log(1 +0.028/365)) ≈ 0.171461/0.0121598

  t ≈ 14.1

It would take about 14.1 years for the value to reach $13,060.

8 0
3 years ago
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