The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.
<u>Step-by-step explanation</u>:
ABCD is a quadrilateral with their opposite sides are congruent (equal).
The both pairs of opposite sides are given as AB = 3 + x
, DC = 4x
, AD = y + 1
, BC = 2y.
- AB and DC are opposite sides and have same measure of length.
- AD and BC are opposite sides and have same measure of length.
<u>To find the length of AB and DC :</u>
AB = DC
3 + x = 4x
Keep x terms on one side and constant on other side.
3 = 4x - x
3 = 3x
x = 1
Substiute x=1 in AB and DC,
AB = 3+1 = 4
DC = 4(1) = 4
<u>To find the length of AD and BC :</u>
AD = BC
y + 1 = 2y
Keep y terms on one side and constant on other side.
2y-y = 1
y = 1
Substiute y=1 in AD and BC,
AD = 1+1 = 2
BC = 2(1) = 2
Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.
Answer:
B C E on edge
Step-by-step explanation:
Answer: C. 84
Step-by-step explanation:
In triangles ABD y BCD:
- AD=CD
- Angle BAD = angle BCD
- BD common side
THEN the triangles are equal because they have two sides and the angle opposite the longest side respectively equal.
CBD = ABD = 42 because the triangles ABD y BCD are equal
ABC = CBD+ABD = 42+42= 84
√196s² = √196 times √s²
s² is the square of 's'
196 is the square of 14
So both can easily come out of the radical.
√196s² = <u>14s</u>
Answer:
Step-by-step explanation:
The solution of the problem has been solved on paper and attached in the attachment section. Kindly refer to that and feel free to ask any doubt.
