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klasskru [66]
3 years ago
9

Its asking to solve for y and the rest​

Mathematics
1 answer:
gladu [14]3 years ago
3 0
First you have to find the missing y
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What is the solution of the system of equations? y = –3x + 8 y = –5x – 2
jekas [21]
y=-3x+8 \\ y=-5x-2 \\  \\ -3x+8=-5x-2 \\ -3x+5x=-2-8 \\ 2x=-10 \\ x=- \frac{10}{2}  \\ x=-5 \\ y=-3(-5)+8=15+8=23  \\ \\ \boxed{-5,23}
6 0
3 years ago
Read 2 more answers
Consider the function f(x)=x3+3x2â51x+91. What is the remainder if f(x) is divided by (x+9)? Do not include (x+9) in your answer
makkiz [27]

Answer:

The remainder is 64

Step-by-step explanation:

Consider the function f(x)=x^3+3x^2-51x+91

Use synthetic division to divide by x+9

x+9=0, x=-9

divide the given f(x) by -9 using synthetic division

-9               1           3       -51       91

                  0          -9     54        -27              

         --------------------------------------------------

                  1           -6      3         64

The remainder is 64

                 

         

5 0
3 years ago
Nike marks up the original cost of all of the shoes they sell by 30%. Andre wants to buy a pair of shoes that has a price tag of
Kisachek [45]

Answer:

$90

Step-by-step explanation:

The shoes now cost 130% of the original cost

The original cost is 100%

Take the new amount and divide it by 130:

117/130 = .90

Then multiply that number by 100 to get the original percent

.90 x 100 = $90

To check, multiply $90 by 130% or 1.30 to make sure that a 30% increase makes the product $117

$90 x 1.30 = $117

7 0
2 years ago
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
2 years ago
Theo earns £20 one weekend.
Colt1911 [192]

Answer:

He spend on bus fares £7.50

4 0
3 years ago
Read 2 more answers
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