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klasskru [66]
3 years ago
9

Its asking to solve for y and the rest​

Mathematics
1 answer:
gladu [14]3 years ago
3 0
First you have to find the missing y
You might be interested in
Can anybody help me on this
solong [7]

9514 1404 393

Answer:

  a. x = 13/7

  b. j = 3

  c. y = 2

  d. p = 25

Step-by-step explanation:

Here, it is convenient to combine like terms first. When you do that, you see that one side of the equation has a mix of a constant term and a variable term. Choose the term that matches the kind of term present on the other side of the equation (constant or variable), then add its opposite to both sides. Finally, divide by the coefficient of the variable.

__

a. 3x +13 = 10x . . . . combine like terms

  13 = 7x . . . . . . . . . subtract 3x

  13/7 = x . . . . . . . . divide by the coefficient of x

__

b. 10j -20 = 10 . . . . combine like terms

  10j = 30 . . . . . . . . add 20

  j = 3 . . . . . . . . . . . divide by 10

__

c. 6y = 14 -y . . . . . . combine like terms

  7y = 14 . . . . . . . . . add y

  y = 2 . . . . . . . . . . divide by 7

__

d. p + 8 = 33 . . . . . . combine like terms

  p = 25 . . . . . . . . .  add -8

_____

<em>Comment on solving equations</em>

In these "2-step" equations, the first step (after simplifying, combining like terms) is to "separate the variable and constant terms". The basic idea is to determine what term you don't want where it is, then add its opposite to both sides of the equation.

You can do anything you like to the equation, provided you do the same thing to both sides. When we say "subtract 3x," for example, we mean 3x is subtracted from both sides of the equation. This is an example of the use of the addition property of equality.

The same goes for multiplication or division. You can multiply or divide by anything you like, as long as you do the same thing to both sides of the equation. In the above, "divide by 7," for example, means both sides of the equation are divided by 7.

3 0
3 years ago
Hayley begins solving this problem by combining like terms. 3x + 5x = 10 Which problem begins the same way? A) 5x = 20 B) 3(x +
joja [24]

Solution: The given equation is →3 x+ 5 x=10

As you can see in the above equation on left side of equation the two terms are variables and on right side of equation the term is a constant term.Also you can see there is an operation called addition between the two variables on left side of equation.

In option (A), there is only a single term on right as well as left,so this can't be true.

In option (B), there is a constant and variable on left side of equation.So this is also untrue.

In option (C), variable being divided by numerator, so this is also untrue.

Option (D)3 x - 2 x = 10,  is surely correct , because there are two variables on left side of equation and one constant on right side of equation, and there is an operation called subtraction between them .

6 0
3 years ago
1/7 divided by 20/21
Sedbober [7]

Answer: 3/20

Step-by-step explanation: (1/7) :(20/21) = (1/7 )· 21/20 = 21/(7·20)= 3/20

7 0
3 years ago
I need halp puh-lease
kozerog [31]
The answer should be 6! all you have to do is plug the numbers into the equation!
it would be like this:
-1^2+3^2+(-1)-3
doing all of that would equal 6!
4 0
3 years ago
Read 2 more answers
Anybody have a proper answer?
maks197457 [2]
The answer would be 40
3 0
3 years ago
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