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Alex17521 [72]
3 years ago
7

Elemental iodine (I 2) is a solid at room temperature. What is the major attractive force that exists among different I 2 molecu

les in the solid?
Chemistry
1 answer:
Ulleksa [173]3 years ago
7 0

Explanation:

As I_{2} is a covalent compound because it is made up by the combination of two non-metal atoms. Atomic number of an iodine atom is 53 and it contains 7 valence electrons as it belongs to group 17 of the periodic table.

Therefore, sharing of electrons will take place when two iodine atoms chemically combine with each other leading to the formation of a covalent bonding.

Hence, weak forces like london dispersion forces will be present between a molecule of I_{2}.

The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

thus, we can conclude that london dispersion force is the major attractive force that exists among different I_{2} molecules in the solid.

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Answer:

the answer is fe20 Hope this helps!

Explanation:

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2 years ago
which of the following is the name given to the pairs of valence electrons that do not participate in bonding in diatomic oxygen
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The answer to your question is

D: Unshared Pair

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A compound has a molar mass of 86.0 g/mol and an empirical formula of C3H7 what is the molecular formula
zmey [24]
The formula for the molecular formula is molar mass/ empirical formula

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3 years ago
A typical person has an average heart rate of 75.0 beats/min. Pay close attention to significant figures in this question.
frozen [14]

The number of beats  the person have in 1.7 years is  6.7 x 10⁷ beats.

<h3>Number of beats of the person</h3>

The number of beats of the person is calculated as follows;

n = bt

where;

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n = 67,014,000

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Thus, the number of beats  the person have in 1.7 years is  6.7 x 10⁷ beats.

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3 0
1 year ago
What is the equation for the reaction of magnesium and iron 2 oxide
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<em>Maybe</em>

<em>Mg+</em><em>Fe2O3</em><em>→</em><em>F</em><em>e</em><em>+</em><em>MgO</em>

<em>hope</em><em> it</em><em> helps</em>

8 0
2 years ago
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