3 years ago

What is the oxidation state of Fe(s)

Chemistry

1 answer:

ad-work [718]3 years ago

8 0

The oxidation state is zero for Fe (s)

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A rectangle solid of unknown density is 5 m long two meters high and 4 meters wide. The mass of this solid is 300 grams. Find th

aksik [14]

D= M/V so, D=300/40 wich is 7.5 so D= 7.5g/m3

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3 years ago

If the pH of an acid is 4.0, what is the pOH?

LiRa [457]

Well from my research I've calculated that pH + pOH = 14.00. in conclusion
pOH = 14.0 - 4.0 and so forth that equals 10.0 your welcome

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3 years ago

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Balance the equation<br> N2O5 + H2 -> NH3 + H2O

Lubov Fominskaja [6]

Answer:

I hope this is it. I'm not really sure.

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3 years ago

The azide ion, n−3, is a symmetrical ion, all of whose contributing structures have formal charges. draw three important contrib

stich3 [128]

Explanation:

Contributing structures are the resonating structures which are formed due to the delocalization of electrons in a molecule.

The azide ion that is $N^{-}_3$ , is a symmetrical ion, all of whose contributing structures have formal charges.

Lone pair of central nitrogen atom in azide ion is in conjugation with the neighboring nitrogen atoms.

Contributing structures of azide ion are drawn in the image attached.

5 0

3 years ago

Caed for this question.

OLga [1]

Answer:

0.962 atm.

97.4 kPa.

731 torr.

14.1 psi.

97,434.6 Pa.

Explanation:

Hello.

In this case, given the available factors equaling 1 atm of pressure, each required pressure turns out:

- Atmospheres: 1 atm = 760 mmHg:

$p=731mmHg*\frac{1atm}{760mmHg} =0.962atm$

- Kilopascals:: 101.3 kPa = 760 mmHg:

$p=731mmHg*\frac{101.3kPa}{760mmHg} =97.4kPa$

- Torrs: 760 torr = 760 mmHg:

$p=731mmHg*\frac{760 torr}{760mmHg} =731 torr$

- Pounds per square inch: 14.69 psi = 760 mmHg:

$p=731mmHg*\frac{14.69}{760mmHg} =14.1psi$

- Pascals: 101300 Pa = 760 mmHg:

$p=731mmHg*\frac{101300Pa}{760mmHg} \\\\p=97,434.6Pa$

Best regards.

5 0

3 years ago