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3 years ago

In the diagram shown,

Mathematics

1 answer:

stich3 [128]3 years ago

8 0

Answer:

1/2 * (5+3) * 6 = 24 cm^2

Step-by-step explanation:

Perimeter is 20

and it's a rectangle so 2x + 12= 20

x is 4 so one of parallel side of trapezium is 9-4 or 5 then just apply formula for area of trapezium

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Room a has 9 rows of seats with seats in each row room b had three times as many seats as room a how many seats wre there in bot

anastassius [24]

Step-by-step explanation:

162.

6 0

2 years ago

Please help with #3a-f.

Igoryamba

When it says f(x) and x is replaced with a number, it just means replace the x in the equation with that number.

(Simpler) Way to solve using the graph:
Go to where x = -4 (4 spaces right of the center) and look above and below it for the line. Wherever the line is, is the answer. So f(-4) = 2 because when x is -4, the y value is 2.

Example of solving with an equation:
f(3) = 2
f(3) = 2(3)
f(3) = 6

You create an equation for the line, than substitute -4 in to the equation.

6 0

2 years ago

Students at Westbrook middle school hold green team meetings to plan ways to help protect the environment. This week there are 1

ICE Princess25 [194]

Answer:

160 members.

Step-by-step explanation:

Please consider the complete question.

Students at Westbrook Middle School hold green team meetings to plan ways to help protect the environment. This week there are 144 members at the meeting, which is 90% of the total group. What is the total number of green team members?

Let x represent total number of green team members.

90% of total number of green team members would be $\frac{90}{100}x=0.90x$ .

Now we will equate 90% of total number of green team members with 144 and solve for x as:

$0.90x=144$

$\frac{0.90x}{0.90}=\frac{144}{0.90}$

$x=160$

Therefore, the total number of green team members is 160.

8 0

3 years ago

Find the sum of all natural numbers between 25 and 210 which are either divisible by 3 or divisible by 4? Please let me know I

Ray Of Light [21]

Let S be the sum of the integers 25-210:

S = 25 + 26 + 27 + … + 208 + 209 + 210

Let S₃, S₄, and S₁₂ denote the sums of the integers in S that are multiples of 3, 4, or 12, respectively. We'll also count how many terms each sum involves; it'll be useful later.

S₃ = 27 + 30 + 33 + … + 204 + 207 + 210 … … … (62 terms)

S₃ = 3 (9 + 10 + 11 + … + 68 + 69 + 70)

S₄ = 28 + 32 + 36 + … + 200 + 204 + 208 … … … (46 terms)

S₄ = 4 (7 + 8 + 9 + … + 50 + 51 + 52)

S₁₂ = 36 + 48 + 60 + … + 180 + 192 + 204 … … … (15 terms)

S₁₂ = 12 (3 + 4 + 5 + … + 15 + 16 + 17)

Let's look at S₃ :

S₃ = 3 (9 + 10 + 11 + … + 68 + 69 + 70)

By reversing the order of the sum, we get

S₃* = 3 (70 + 69 + 68 + … + 11 + 10 + 9)

Of course S₃ = S₃*, I'm just calling it something else temporarily. Notice that every term in the same position of either sum adds up the same number.

9 + 70 = 79

10 + 69 = 79

11 + 68 = 79

and so on. Then

S₃ + S₃* = 3 (79 + 79 + 79 + … + 79 + 79 + 79)

2S₃ = 3 × 62 × 79 ==> S₃ = 7,347

We can compute the other two sums in the same way.

S₄ = 4 (7 + 8 + 9 + … + 50 + 51 + 52)

S₄* = 4 (52 + 51 + 50 + … + 9 + 8 + 7)

==> 2S₄ = 4 × 46 × 59 ==> S₄ = 5,428

S₁₂ = 12 (3 + 4 + 5 + … + 15 + 16 + 17)

S₁₂* = 12 (17 + 16 +15 + … + 5 + 4 + 3)

==> 2S₁₂ = 12 × 15 × 20 ==> S₁₂ = 1,800

Then the sum you want is

S₃ + S₄ - S₁₂ = 10,975

We subtract S₁₂ because each of its terms is counted twice (once in S₃ and again in S₄).

6 0

2 years ago

Q3. If I = (P × R × T)/100, find T if I = 80 Rs, P = 400 Rs., R = 10 Rs. (2)

sukhopar [10]

9514 1404 393

Answer:

T = 2

Step-by-step explanation:

Fill in the given numbers and solve for T.

I = PRT/100

80 = 400·10·T/100

80 = 40T . . . . . . . . . . . . simplify

80/40 = T = 2 . . . . . . . . divide by the coefficient of T

4 0

2 years ago

Read 2 more answers