We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
might be 3
Step-by-step explanation:
Answer:
y=2x+1
Step-by-step explanation:
Parallel = gradients are the same
Example: y=2/4x+5
Perpendicular = gradients are the inverse of each other
Example: y= -4/2x+1
Any equation would be correct unless the gradient is 2/4 or -4/2
Answer:
Adjacent angles
Step-by-step explanation:
Total cost= (24 times 4)+(10 times 2)
96 + 20 = 116
cost: $116
