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3 years ago

How do I answer the question in the photo

Mathematics

1 answer:

gregori [183]3 years ago

3 0

Answer:

Step-by-step explanation:

Order the numbers from greatest to least. Then subtract the smallest value to the largest value in the set.

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A chimp is taking a multiple - choice test of course the chip can't read and his guessing for every question. If there are 4 cho

tia_tia [17]

Answer:

Step-by-step explanation:

He will guess correctly 25% of the time.

He has 84 questions

25% of 84

.25 * 84

We should expect that he will get 21 questions correct

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3 years ago

What temperature is 15 degrees lower than 7 degrees celsius

VikaD [51]

7-15= -8
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3 years ago

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allochka39001 [22]

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3 years ago

The coordinates of a triangle

Molodets [167]

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3 years ago

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

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3 years ago