The projectile has constant horizontal speed all the time and we can use this formula
x=Vax*t, where t is time it (projectile) takes to reach x=1000m
t=x/Vax=1000/50=20s
As we know we can split projectile trajectory in two parts and the time for each part is equal. We can conclude that time t=20s belong to first part where projectile is going up.
Formula for this type of movement is y=Vay-(gt∧2)/2
If we take acceleration of gravity g=10m/s∧2
we get y=200*20-(10*20∧2)/2=4000-2000=2000m
But if I calculate time it takes the highest point I get
t=Vay/g=200/10=20s
The highest point for that time is
y= H=Vay∧2/2g=200∧2/2*10=40000/20=2000m
This happened because the projecile is fired from the edge of a cliff which is above the sea line.
Good luck!!!
If you want to find the x-intercept, you replace y in the equation with 0 and solve the equation for x.
If you want to find the y-intercept, you replace x in the equation with 0 and solve the equation for y.
Example:
Answer:
20.
Step-by-step explanation:
P(5,3) = 5! / 3!
= (5*4*3*2*1) / (3*2*1)
= 20.
Answer:
x = 4, y = 3/5
Step-by-step explanation:
3x - 5y = 7
2x + 5y = 13
add the equations
5x = 20
x = 4
plug in x for one of the equations
2(5) + 5y = 13
10 + 5y = 13
5y = 3
y = 3/5
