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ANTONII [103]
3 years ago
12

Please someone I need the right answer will give brainiest if right​

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0

Answer:

C. Because (-3)^2 is NOT equal to -9

Step-by-step explanation:

zvonat [6]3 years ago
8 0

Answer:

C

Step-by-step explanation:

√-9 is   3i.

Since there is a negative in the root, you can't have a regular number as the answer.

It askes why -3 is not the answer. Because -3 squared is 9, not -9.  

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The rectangle has an area of x square plus 15 square meters and a width of X plus 3
hammer [34]

Answer:

x + 5

Step-by-step explanation:

4 0
3 years ago
How do you estimate 2,641 x 9
ASHA 777 [7]
To estimate 2641 x 9 is that you round each number. so it would be 2641 to 2640 and the 9 would round to 10. 2640 x 10
3 0
2 years ago
Read 2 more answers
K is no greater than 9?<br><br> Write&gt;,&lt;.
alekssr [168]
Greater than symbol is ">"
But since he mentioned "NO greater than" then it's the opposite of greater than, which means "K" is less than "9"

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4 0
3 years ago
A rectangular paperboard measuring 29in long and 20in wide has a semicircle cut out of it, as shown below.
katen-ka-za [31]

Here, we are required to find the area of the paper board given after the semicircle is cut out of it

Area of the paper board thatremains is 423 in²

Length = 29 in

Width = 20 in

Area of a rectangle = length × width

= 29 in × 20 in

= 580 in²

Area of a semi circle = πr²/2

π = 3.14

r = diameter / 2 = 20 in / 2 = 10 in

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= 3.14 × (10 in)² / 2

= 3.14 × 100 in² / 2

= 314 in²/2

= 157 in²

The semicircle is cut out of the rectangle

Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle

Area of the paper board that remains = Area of a rectangle - Area of a semi circle

= 580 in² - 157 in²

= 423 in²

brainly.com/question/16994941

6 0
3 years ago
a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?
Kruka [31]
Find the length of the radius.

r= \sqrt{(3-(-4))^2+(5-6)^2}&#10;\\r =  \sqrt{7^2+(-1)^2}&#10;\\r= \sqrt{50} &#10;\\  r=5 \sqrt{2}

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)&#10;\\y-6= \frac{5-6}{3-(-4)}  (x-(-4))&#10;\\y-6=- \frac{1}{7} (x+4)&#10;\\7y-42=-x-4&#10;\\x+7y-38=0 

The distance from B(x, y) to C(3, 5) is 5√2.
\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} &#10; \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 &#10;\\(x-3)^2+(y-5)^2=50

Solve system of equations.
x+7y-38=0&#10;\\(x-3)^2+(y-5)^2=50&#10;\\&#10;\\x=38-7y&#10;\\(38-7y-3)^2+(y-5)^2=50&#10;\\(35-7y)^2+(y-5)^2=50&#10;\\1225-490y+49y^2+y^2-10y+25-50=0&#10;\\50y^2-500y+1200=0&#10;\\y^2-10y+24=0&#10;\\y^2-6y-4y+24=0&#10;\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4&#10;

x_1=38-7y_1=38-7 \times 6 = 38-42=-4&#10;\\x_2=38-7y_2=38-7 \times 4 = 38-28=10&#10;

Point B could have coordinates
\\&#10;\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)&#10;

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).
8 0
3 years ago
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