<h3><u>Option A</u></h3>
is the required equation to calculate width of rectangular frame that has a total area of 140 square inches.
<h3>
<u>Solution:</u></h3>
Given that,
Length of a rectangular frame is given as 2x + 10
Width of the rectangular frame is given as 2x + 6
Total area = 140 square inches
<em><u>The area of rectangular frame is given as:</u></em>
Plugging in values, we get
This is the required equation to calculate width of rectangular frame
Solve the above quadratic equation to get the value of "x"
<em><u>Use the quadratic equation formula:</u></em>
Here a = 4 ; b = 32 ; c = -80
x = 2 or x = -10
Now measurement cannot be negative, so taking the positve value of "x", we can calculate the width
So put "x" = 2
Width of the rectangular frame = 2x + 6 = 2(2) + 6 = 10
Thus the width of frame is 10 inches
Answer:
1600
Step-by-step explanation:
<h3>
(-2)^{4} x (-10)^{2}[/tex]</h3><h3>
</h3><h3>
Evaluate it: 2^{4} x -10^{2}</h3><h3>
Multiply: 16x100</h3><h3>Finally you get:</h3><h3>1600</h3>
Answer:
21.715 degrees
Step-by-step explanation:
There are 14 vertexes (vertices) for a 14-gon. It is 'regular' so all these angles are equal. So the exterior angle of each is 180-154.285 = 21.715 degrees.
Answer: p = -8.
Step-by-step explanation: Since [tex]1.6/(-0.4) = -4[\tex],
[tex] p + \frac{1.6}{-0.4} = -12 [\tex]
[tex] p -4 = -12 [\tex]
[tex] p = -12 + 4 [\tex]
[tex] p = -8 [\tex]
