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ycow [4]
3 years ago
12

How do u find average rate of change

Mathematics
2 answers:
Ann [662]3 years ago
7 0
When you calculate the average rate of change of a function, you are finding the slope of the secant line between the two  points . So it would look like this f(x)=x^2 and f(x+h)=(x+h).Therefore,the slope  of the secant line between any two points on this function is 2x+h.Hoped this helped!!
xenn [34]3 years ago
5 0
To find the average rate of change, its a secant line. 
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The car went 12.05 miles per gallon of gas and went 36.15 miles per hour.

(Just divide the total amount of miles by each value to get both of these answers.)


4 0
3 years ago
Help me on this question
NeX [460]

Answer:

x = 18

Step-by-step explanation:

Vertically Opposite Angles are equal..

so,

x + 54 = 4x \\ 54 = 4x - x \\ 54 = 3x \\  \frac{54}{3} =    \frac{3x}{3}  \\ 18  = x

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2 years ago
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TiliK225 [7]
Should be the second one. 
4 0
2 years ago
I know the answer but I need to explain how to get the answer. Please help❤️
kondaur [170]

Answer:

730, 735, 740

Step-by-step explanation:

Let the three consecutive multiples of 5 be, x, x+5 and x+10

Given,

x + x+5 + x+10 = 2205

3x + 15 = 2205

Subtract 15 from both sides,

3x = 2205 - 15

3x = 2190

Divide both sides by 3,

x = 2190/3 = 730

So, x= 730

x+5 = 735

x+10 = 740

5 0
2 years ago
In a recent​ year, a poll asked 2362 random adult citizens of a large country how they rated economic conditions. In the​ poll,
Harman [31]

Answer:

a) The 99% confidence interval is given by (0.198;0.242).

b) Based on the p value obtained and using the significance level assumed \alpha=0.01 we have p_v>\alpha so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

c) \alpha=0.01

Step-by-step explanation:

<em>Data given and notation   </em>

n=2362 represent the random sample taken

X represent the people who says that  they would watch one of the television shows.

\hat p=\frac{X}{n}=0.22 estimated proportion of people rated as​ Excellent/Good economic conditions.

p_o=0.24 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  <em> </em>

<em>Concepts and formulas to use   </em>

We need to conduct a hypothesis in order to test the claim that 24% of people are rated with good economic conditions:  

Null hypothesis:p=0.24  

Alternative hypothesis:p \neq 0.24  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Part a: Test the hypothesis

<em>Check for the assumptions that he sample must satisfy in order to apply the test   </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.  

b) The sample needs to be large enough

np = 2362x0.22=519.64>10 and n(1-p)=2364*(1-0.22)=1843.92>10

Condition satisfied.

<em>Calculate the statistic</em>  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.22 -0.24}{\sqrt{\frac{0.24(1-0.24)}{2362}}}=-2.28

The confidence interval would be given by:

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The critical value using \alpha=0.01 and \alpha/2 =0.005 would be z_{\alpha/2}=2.58. Replacing the values given we have:

0.22 - (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.198

 0.22 + (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.242

So the 99% confidence interval is given by (0.198;0.242).

Part b

<em>Statistical decision   </em>

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided is \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

So based on the p value obtained and using the significance level assumed \alpha=0.01 we have p_v>\alpha so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

Part c

The confidence level assumed was 99%, so then the signficance is given by \alpha=1-confidence=1-0.99=0.01

6 0
2 years ago
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