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ikadub [295]
3 years ago
15

What is the value of 2/5x3/5

Mathematics
2 answers:
Lapatulllka [165]3 years ago
7 0

2/5x3/5

Mutiply the numerators together

(2)(3)= 6

Mutiply the denominators together

(5)(5)= 25

Answer: 6/25

inessss [21]3 years ago
3 0

Answer:

6/25

Step-by-step explanation:

When multiplying fractions, you multiply across each row.

2/5 * 3/5

<u />

<u>2   *   3</u>

5   *   5

<u>6</u>

5

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What is 4x squared minus x squared
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Answer:

3x^2 or 3x squared

Step-by-step explanation:

4x^2-x^2=3x^2

4x squared-x squared equals x squared

when subtracting squared it's like subtracting normal numbers

3 0
3 years ago
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Gia's ruler is divided into tenths of an inch. What fraction of an inch represents the greatest possible measurement error due t
miskamm [114]
The greatest measurement error s 1/10 of an inch, which is 10% of an inch.

Therefore the greatest measurement error is 1/10 or 10%.

Answer: 0.1 or 10% per inch.
4 0
3 years ago
What is (t - 7 )3? ive tried it many times and i cant get it. Thanks !
mina [271]

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3 years ago
A recent survey was conducted to compare the cost of solar energy to the cost of gas or electric energy. Results of the survey r
Mariana [72]

Answer:

c) at most 11.1%

Step-by-step explanation:

We have the data that is 97 ± 12, with 97 being the mean and 12 the standard deviation.

Now, the percentage of people who reached them for less than 73 dollars, if it were a normal distribution:

z = (73 - 97) / 12 = - 2

so it would be, a probability of 0.0228 or 0.228%.

But we don't know what distribution it has, but we can get an idea.

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4 0
3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
3 years ago
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