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timurjin [86]
4 years ago
8

Help I have to write slope intercept form of the equation

Mathematics
1 answer:
scoundrel [369]4 years ago
3 0
Slope int form:
y = mx + b
since the other line is parallel it will have the same slope as the line you are trying to figure out and it is already in slope intercept form. The slope of the parallel line is 9/4 so our slope will also be 9/4. We can put this in our equation.

y = \frac{9}{4} x + b

Now we need to find b. To do this plug in the coordinate points given to you (3,4)

4 = ( \frac{9}{4} )(3) + b

solve for b

b = 4 - \frac{9 \times 3}{4} = ( \frac{16}{4} - \frac{27}{4} ) = - \frac{ 11}{4}

so the slope int form would be

y = ( \frac{9}{4} )x - \frac{11}{4}
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if you double the input of a function and it results in twice the output and if you triple the input and it result in three time
bearhunter [10]

A function behaving as you state is a linear function, which means that the output varies directly with the input.

So, there exists some constant k \in \mathbb{R} such that your function is in the form

f(x) = kx

In fact, if you double the input, you have

f(2x) = k\cdot(2x) = 2\cdot (kx) = 2f(x)

And similarly

f(3x) = k\cdot(3x) = 3\cdot (kx) = 3f(x)

Note that this is a guess, it may happen that output doubles (triples) if you double (triple) the input, and still the function is not like y=kx.

For example, the function

f(x) = \dfrac{x^3}{3} - 2x^2 + \dfrac{14}{3}x -2

is such that

f(1) = 1,\ f(2) = 2,\ f(3) = 3

So, it may seems that doubling and tripling the input doubles and triples the output, but this is not true for every input, for example,

f(2) = 2,\ f(4) = 6

And so doubling the input didn't double the output.

8 0
4 years ago
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Add. 3x^2 -5x +1 + 2x^2 +9x -6
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Answer:

=5x^2+4x−5

Step-by-step explanation:

Let's simplify step-by-step.

3x2−5x+1+2x2+9x−6

=3x2+−5x+1+2x2+9x+−6

Combine Like Terms:

=3x2+−5x+1+2x2+9x+−6

=(3x2+2x2)+(−5x+9x)+(1+−6)

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hjlf

Answer:

see the explanation

Step-by-step explanation:

<u><em>Verify each case</em></u>

Part 1) The graph show two identical lines, then the system has infinitely many solutions

Part 2) The graph show two perpendicular lines.

Remember that the solution of the system is the intersection point both graphs

The intersection point is (2,6)

therefore

The system has one solution at (2,6)

Part 3) The graph show two intersecting lines at (-6,-2)

Remember that the solution of the system is the intersection point both graphs

The intersection point is (-6,-2)

therefore

The system has one solution at (-6,-2)

8 0
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