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3 years ago

I really need some help, please ASAP

Mathematics

1 answer:

Naddika [18.5K]3 years ago

8 0

A) $94
b) S=8w+54
c) 116=8w+54
-54. -54
62=8w
7.75=w
8 week because she is depositing at the end of the week

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A cylinder has a base radius of 6 feet and a height of 12 feet.What is it's volume in cubic feet, to the nearest tenths place

Neporo4naja [7]

Answer:

$volume = \pi {r}^{2} h \\ = 3.14 \times {6}^{2} \times 12 \\ = 1357.2 \: {ft}^{3}$

8 0

3 years ago

Help ASAP can u explain a little too? (pls help if u don’t know it don’t answer pls) Thank You:)

larisa [96]

Since they are similar, the dimensions are in the same ratio. L1 = 5, L2 = 15, so they are in a 3:1 ratio. So if V1 = 60, then W1×H1 = 60/5 = 12
W2 must also be 3×W1 and H2 3×H1, and
3×3 = 9. So take 12×9 (W×H1×9) ×15 (L2) = V2
V2 = 12×9×15 = 1620 cm^3

Let me know the right answer when you find out!

8 0

3 years ago

Can u guys help me please dont steal or guess ( will give brainiest for proof)

Novay_Z [31]

Answer:

30 feet

Step-by-step explanation:

To find the distance use a trigonometric ratio. Since we are looking for the hypotenuse and we are given the opposite side we will be using the ration of sine. We can set up the equation like this by using x as the measure we are looking for.

Sin of x=Opposite leg/Hypotnuse

Sin of 30= 15/x

Multiply by x and then divide by Sin of 30 to isolate the x.

x=15/Sin of 30

Plug it in to a calculator.

x=30

4 0

3 years ago

1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav

OLga [1]

Answer:

(1) y=C, $C\neq0$

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant, $C \neq 0$ , has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

$\Rightarrow x=C$ , where $C\neq0$ .

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0

3 years ago

Find the equation of the line that contains the point (3,9) and is parallel to the line y=4x+1. Write the line in slope-intercep

Aleksandr-060686 [28]

Y = 4x + 1....slope here is 4. A parallel line will have the same slope

y = mx + b
slope(m) = 4
(3,9)...x = 3 and y = 9
now we sub and find b, the y int
9 = 4(3) + b
9 = 12 + b
9 - 12 = b
-3 = b

so ur parallel equation is : y = 4x - 3

5 0

3 years ago