Question

If f(x) is discontinuous, determine the reason.%20%2B%204%3B%20x%20%5Cleq%201%7D%20%5Catop%20%7Bx%2B4%3B%20x%20%5C%20%20%5Ctextgreater%20%5C%20%201%7D%7D%20%5Cright." id="TexFormula1" title="f(x) = \left \{ {{x^2 + 4; x \leq 1} \atop {x+4; x \ \textgreater \ 1}} \right." alt="f(x) = \left \{ {{x^2 + 4; x \leq 1} \atop {x+4; x \ \textgreater \ 1}} \right." align="absmiddle" class="latex-formula">a. f(x) is continuous for all real numbersb. The limit as x approaches 1 does not exist c. f(1) does not equal the limit as x approaches 1 d. f(1) is not defined

Answer 1

Answer:

a. f(x) is continuous for all real numbers

Step-by-step explanation:

At x = 1

Piece 1:

f(x) = 1² + 4 = 5

Piece 2:

f(x) = 1 + 4 = 5

First piece ends at (1,5)

Second piece starts at (1,5)

So no discontinuity