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3 years ago

89.10-[(1.20x31)+(4.90+7)]

Mathematics

2 answers:

Tamiku [17]3 years ago

7 0

40 because 1.2 x 31 = 37.20 and 4.9 + 7 = 11.90 so 89.10 - 49.10 = 40

lakkis [162]3 years ago

6 0

Answer:

65.3

Step-by-step explanation:

89.10 - [(1.20 × 31)+ (4.90 + 7)]

89.10 - [37.2 + 11.9]

89.10 - 23.8

= 65.3

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The perimeter of a rectangle is 215 feet. The short sides are each 24 feet long, but the lengths of the long sides are unknown.

Nataly_w [17]

Answer:

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Step-by-step explanation:

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kvv77 [185]

Answer:

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3 years ago

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Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

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Vector (ordered pair - polar form)

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Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

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Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

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Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

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