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Sergio039 [100]
3 years ago
8

I need answers for both please!!

Mathematics
1 answer:
alekssr [168]3 years ago
6 0

1 = a

2 = h

have a good day

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I really need help on these please give me the answers.
vodomira [7]
I believe you should do as much work as you can on each of these problems and only then ask for help.  You'll almost always learn more by becoming involved in the thinking and problem solving you encounter here.

|x| + 5 = 13  reduces to   |x| = 13, so x could be either -13 or +13.
3 0
3 years ago
The amount of wall space in his bedroom will determine how much paint he needs.which one is the independent variable and which o
ExtremeBDS [4]

Answer:

Independent- wall  Dependent- amount of paint

Step-by-step explanation:

The independent variable is the variable the experimenter changes or controls and is assumed to have a direct effect on the dependent variable. ... The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.

7 0
2 years ago
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I will report u if you don't answer for real,but if u don't know then don't answer.​
loris [4]

Answer:

the answer is 71 inches.

Step-by-step explanation:

convert 2ft and 1 yards inches

2ft is 24 because 1 foot is 12 inches

1 yard is 36 inches because 1 yard is 3 feet

3×12=36

soo... 36+24+11=71

6 0
3 years ago
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What is vertical stretch?
ki77a [65]
A vertical stretch is the stretching of a line away from the x-axis. 
7 0
3 years ago
Given that tan 0=-4/7 , and 270 degrees <0<360 degrees , what is the exact value of sec0?
Elanso [62]
I take it you meant θ angle, anyway.

we know the tan(θ) = -4/7... alrite, we also know that 270° < θ < 360°, which is another to say that θ is in the IV quadrant, where the adjacent side or "x" value is positive whilst the opposite side or "y" value is negative.

\bf tan(\theta )=\cfrac{\stackrel{opposite}{-4}}{\stackrel{adjacent}{7}}\impliedby \textit{now let's find the \underline{hypotenuse}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{7^2+(-4)^2}\implies \implies c=\sqrt{65}\\\\&#10;-------------------------------\\\\&#10;sec(\theta )=\cfrac{\stackrel{hypotenuse}{\sqrt{65}}}{\stackrel{adjacent}{7}}
6 0
3 years ago
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