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nataly862011 [7]
3 years ago
5

ILL GIVE YOU BRAINLYIST

Chemistry
1 answer:
defon3 years ago
4 0
A b and d trust I done this
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Most elements are _____? <br><br> nonmetals <br> metalloids<br> metals
NARA [144]

Answer:Most elements on the periodic table are metals. Looking at the periodic table shows that most elements are metallic.

Explanation: Sorry if this want what you were looking for

4 0
2 years ago
A mixture of H2 and water vapor is present in a closed vessel at 20°C. The total pressure of the system is 755.0 mmHg.
Masja [62]

THE ANSWER IS: <u>737.5</u>

I JUST TOOK THE QUIZ!!!!

7 0
3 years ago
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What is the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO3 by mass)? (a) Outline the steps necess
RoseWind [281]

Answer:

33.8 m

Explanation:

(a) We want to know the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO₃ by mass).

Step 1: Determine the mass of HNO₃ and water in 100 grams of solution.

Step 2: Convert the mass of HNO₃ to moles.

Step 3: Convert the mass of water to kilograms.

Step 4: Calculate the molality.

(b)

Step 1

In 100 g of solution, there are 68.0 g of HNO₃ and 100 g - 68.0 g = 32.0 g of water.

Step 2

The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 68.0 g are:

68.0 g × (1 mol/63.01 g) = 1.08 mol

Step 3

The mass of water is 32.0 g = 0.0320 kg

Step 4

The molality of HNO₃ is:

m = moles of solute / kilograms of solvent

m = 1.08 mol / 0.0320 kg

m = 33.8 m

5 0
4 years ago
Read 2 more answers
How many grams of BaCl2 are required to make 1.50L of a 0.60M solution?
masha68 [24]

Answer:

187.407g

Explanation:

Moles of solute = Molarity × Liters of solution

Multiply 0.60 M by 1.50L:

0.60 mol/ 1L×1.50L=0.9 mol

To obtain the mass of solute, we will need to the molar mass of BaCl2, which is 208.23g/mol:

Finally, multiply the number of moles by208.23g /mol

0.9mol×208.23g/1mol =187.407g

Boom, you have a mass of:

187.407g

4 0
2 years ago
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If you need to do a 1:20 dilution on a culture to get acceptable plate counts, how many milliliters of original sample will you
aev [14]

Answer:

0.0050 mL

Explanation:

First we <u>divide the final volume by 20</u>:

  • 0.1 mL / 20 = 0.005 mL

So if we add 0.005 mL of the original sample to 0.095 mL of sterile DI water, we're left with 0.1 mL of a 1:20 dilution.

Rounding up 0.005 mL to four decimal places, the answer thus is 0.0050 mL.

4 0
3 years ago
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