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Fynjy0 [20]
3 years ago
5

What is the chemical equation for aluminium chloride

Chemistry
1 answer:
FrozenT [24]3 years ago
6 0

AlCl3 is the chemical equation.

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Toothpaste is an alkali. How could you use the toothpaste to show that red cabbage is an indicator?
Alecsey [184]

Answer:

PUT THE TOOTHPAST ON CABBAGE AND CHECK IT OUT AFTER A DAY

3 0
2 years ago
What are transferred in an oxidation-reduction reaction (1 point)?
madreJ [45]
electrons are transferred    in a oxidation-reduction  reaction

oxidation reduction  chemical equation involve  electrons  transfer   between  two species. In this reduction-oxidation type of chemical equation    oxidation  number of   molecule, atoms or ion  changes  by  gaining or losing  electrons,that is there  an oxidizing  agent and a  reducing agent  in the reaction.
7 0
3 years ago
Explain the terms physical properties of metals Malleability and ductility, and how they used in daily life situation ?​
EastWind [94]

Answer:

Malleability means that metals can be hammered into sheets and foils. For example, aluminium foils are used for wrapping food stuffs, silver foils are used for decorative purposes on sweets and fruits. Ductility means that metals can be drawn into wires. Gold and silver wires are used in ornaments.

and For jewellery and ornaments, gold, platinum and silver are being used. For building purposes, iron and steel can be used. Iron and aluminium are used as utensils. The thermometer uses mercury and helps to monitor the temperature.

Explanation:

please rate as brainliest

7 0
1 year ago
Read 2 more answers
63 C = _____ 63 K 336 K 210 K 163 K
swat32
T K = ºC + 273

T = 63 + 273

T = 336 K

hope this helps!

4 0
4 years ago
Read 2 more answers
Find the pH of a 0.350 M aqueous benzoic acid solution. For benzoic add. Ka = 6.5 x 10^-5.
slava [35]

Answer:

correct option is (a)

The solution would be using this: C6H5COOH = H+ + C6H5COO Ka = 6.5 x 10^-5 = (H+)(C6H5COO-) over

(C6H5COOH)

Let X = moles per liter (H+) and also = moles per liter (C6H5COO-)

Ka = 6.5 x 10^-5 = (X)(X) over .350 molar = acid solution 6.5 x 10^-5 = X^2 over .350

X^2 = 6.5 x 10^-5 times .350 which = 2.275 x 10^-5

x = V2.275 x 10^-5

X = 1.5083 x 10^-5 moles per liter H+

pH = -log(H+) = -log 1.5083 x 10^-5 which

= 4.6215

7 0
3 years ago
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